Q4: A road is to be redesigned using a parabolic vertical curve to provide clearance beneath a bridge (see Figure below). The (PC OR PVC) has chainage 1140.00m, with an RL of 125.536m. A bridge at chainage 1300.00 has an RL = 128.5m at its lowest point. You must provide 4.5m clearance from the underside of the bridge, and the parabola will finish with a succeeding gradient, G 2 = +3.6%. G1= ? 1. What is the length of the curve? 2. What is the initial gradient G1?( PC Ch 1140 RL 125.536 G1 = ? J 11 Point PVC PVT Easting (m) 122.8 326.1 Here Ah = 4.5 P Northing (m) 40.2 76.3 Ch 1300 RL 128.5 G2 = +3.6% PT RL=124.00 Elevation (m) 125.536 ?
Q4: A road is to be redesigned using a parabolic vertical curve to provide clearance beneath a bridge (see Figure below). The (PC OR PVC) has chainage 1140.00m, with an RL of 125.536m. A bridge at chainage 1300.00 has an RL = 128.5m at its lowest point. You must provide 4.5m clearance from the underside of the bridge, and the parabola will finish with a succeeding gradient, G 2 = +3.6%. G1= ? 1. What is the length of the curve? 2. What is the initial gradient G1?( PC Ch 1140 RL 125.536 G1 = ? J 11 Point PVC PVT Easting (m) 122.8 326.1 Here Ah = 4.5 P Northing (m) 40.2 76.3 Ch 1300 RL 128.5 G2 = +3.6% PT RL=124.00 Elevation (m) 125.536 ?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:Q4: A road is to be redesigned using a parabolic vertical curve to provide clearance beneath a bridge
(see Figure below). The (PC OR PVC) has chainage 1140.00m, with an RL of 125.536m. A bridge at
chainage 1300.00 has an RL = 128.5m at its lowest point. You must provide 4.5m clearance from the
underside of the bridge, and the parabola will finish with a succeeding gradient, G 2=+3.6 %. G1= ?
1. What is the length of the curve?
2. What is the initial gradient G1?
PC
Ch 1140
RL 125.536
G1= ?
L =?
Point
PVC
PVT
Easting
(m)
122.8
326.1
Here De
bridkje
Ah = 4.5
Northing
(m)
Ch 1300
RL 128.5
40.2
76.3
G2 = +3.6%
RL = 124.00
PT
Elevation
125.536
?
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