Prob. 5.4-32. Sketch the shear diagram and the moment diagram for the beam AC in Prob. 5.4-12. Use the Graphical Method to sketch V(x) and M(x), use the information in Table 5.1 in sketching the shear diagram and the moment diagram. Draw the requested shear-force and bending-moment dia- grams approximately to scale. Label all critical ordinates, including the maximum and minimum values, and indi- cate the sections at which these occur. 1.5 kips/ft 8 ft 12 ft

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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This is a mechanics of material question please show all steps clearly please show the given, what is to be found, and a free body diagram.
TABLE 5.1 Shear and Moment Diagram Features
Equation
dV
dx
-p(x) (Eq.5.2)
AV P (Eq. 5.4)
dM
dx
V₁ - V₁ = p(x)dx (Eq.5.6)
= V(x) (Eq.5.3)
AM-M₁ (Eq. 5.5)
Shear
Diagram
V
1. Slope of shear diagram equals value of load
M₁ V₁
M₂-M₁ = V(x)dx (Eq.5.7)
M₁ V₁
Load
Diagram
P
M₁ V₁
(1
2. Jump in shear equals value of concentrated load
M₁ V₁
P2
Po
3. Change in shear equals area under distributed-load diagram
(Area)
V₂ M₂
M₁ V₁
Mo
V₂ M₂
5. Jump in moment equals - (value
V₂ - V₁ = (Arca),
4. Slope of moment diagram equals value of shear
V₂ M₂
V₂ M₂
V₁
V₂ M₂
V₂ M₂
V₁
Slope = P₁
V₁
Po
V₁₂
V₁
Positive V-jump
Prat 5.5-3
concentrated couple)
6. Change in moment equals area under shear diagram
V₂
(Area)y
V₂
V₂
M₁D
M₁
M₁
M₁
Moment
Diagram
M
M₁
Slope = V₁
Mo
M₂
M₂
M₂
M₂
M₂
Negative M-jump
M₂
M₂-M₁ = (Area)y
Transcribed Image Text:TABLE 5.1 Shear and Moment Diagram Features Equation dV dx -p(x) (Eq.5.2) AV P (Eq. 5.4) dM dx V₁ - V₁ = p(x)dx (Eq.5.6) = V(x) (Eq.5.3) AM-M₁ (Eq. 5.5) Shear Diagram V 1. Slope of shear diagram equals value of load M₁ V₁ M₂-M₁ = V(x)dx (Eq.5.7) M₁ V₁ Load Diagram P M₁ V₁ (1 2. Jump in shear equals value of concentrated load M₁ V₁ P2 Po 3. Change in shear equals area under distributed-load diagram (Area) V₂ M₂ M₁ V₁ Mo V₂ M₂ 5. Jump in moment equals - (value V₂ - V₁ = (Arca), 4. Slope of moment diagram equals value of shear V₂ M₂ V₂ M₂ V₁ V₂ M₂ V₂ M₂ V₁ Slope = P₁ V₁ Po V₁₂ V₁ Positive V-jump Prat 5.5-3 concentrated couple) 6. Change in moment equals area under shear diagram V₂ (Area)y V₂ V₂ M₁D M₁ M₁ M₁ Moment Diagram M M₁ Slope = V₁ Mo M₂ M₂ M₂ M₂ M₂ Negative M-jump M₂ M₂-M₁ = (Area)y
Prob. 5.4-32. Sketch the shear diagram and the moment
diagram for the beam AC in Prob. 5.4-12.
Use the Graphical Method
to sketch V(x) and M(x),
use the information in Table 5.1 in
sketching the shear diagram and the moment diagram.
Draw the requested shear-force and bending-moment dia-
grams approximately to scale. Label all critical ordinates,
including the maximum and minimum values, and indi-
cate the sections at which these occur.
1.5 kips/ft
8 ft
20 kips
12 ft
Transcribed Image Text:Prob. 5.4-32. Sketch the shear diagram and the moment diagram for the beam AC in Prob. 5.4-12. Use the Graphical Method to sketch V(x) and M(x), use the information in Table 5.1 in sketching the shear diagram and the moment diagram. Draw the requested shear-force and bending-moment dia- grams approximately to scale. Label all critical ordinates, including the maximum and minimum values, and indi- cate the sections at which these occur. 1.5 kips/ft 8 ft 20 kips 12 ft
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