Prior Probabilities for A1 and A2: P(A1)=0.20, P(A2)=0.40, (A1) and (A2) are mutually exlcusive. Suppose P(B|A1)=0.20, P(B|A2)=0.05 P(B)=?
Q: P(A)=0.56,P(B)=0.54,P(B∪A)=0.91P(A)=0.56,P(B)=0.54,P(B∪A)=0.91 Find the following probabilities.…
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Q: The prior probabilities of events A1, A2 and A3 if P(A1)=0.20, P(A2)=0.50 and P(A3)=0.30. The…
A: Given that , P(A1) = 0.20P(A2) = 0.50P(A3) = 0.300.500.400.30
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Q: Use the z-table to find the following probabilities P(0 1.24)
A: P(0 < z < 2.46)
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A: 0 0.14844 -2.43056 5.9076219136 0.877 1 0.15625 -1.43056 2.0465019136 0.320 2 0.23756 -0.43056…
Q: =. Compute P(Β n Α1) , P(Β n A2), and Ρ(BnA:). P(Βη Αι) = P(Bn A2) = P(Β η As) =| b. Apply Bayes'…
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Q: Find the following probabilities: A. P(z > 1.96) B.P(-1.65<z<1.65) C.P(-2.33<z<o) Explain.
A: (A) The value of P(z > 1.96) is, Therefore, the required probability is, 0.0250.
Q: The probability of flu symptoms for a person not receiving any treatment is 0.034. In a clinical…
A: Given, n = 817 p = 0.034
Q: P(A)=0.56,P(B)=0.52,P(B∩A¯¯¯¯)=0.32P(A)=0.56,P(B)=0.52,P(B∩A¯)=0.32 Find the following…
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Q: Given that P(A)P(A) = 0.49, P(B)P(B) = 0.63, and P(A∣B)P(A∣B) = 0.46, find the probabilities:…
A: As per our guidelines we can solve first three sub part of question and rest can be reposted.…
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A: error probability for n=10,20,25 can be calculated as
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Q: you are givin the information that P(A) = 30 and P(B) = 0.40. Do you have enough information to…
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Q: In a computer instant messaging survey, respondents were asked to choose the most fun way to flirt,…
A: GivenP(D) = 0.750where D is directly in person
Q: Use the following probabilities to answer the question. Round to 4 decimal places.…
A: Solution: Given information: P(A) =0.33 P(B)=0.62 P(A∩B)=0.05
Q: The U.S. Census Bureau provides data on the number of young adults, ages 18-24, who are living their…
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Q: (1) P(T) 0.306 (ii) P(TC) 0.694 (iii) P(CIT) 0.391 (iv) P(LIT) 0.285 Complete the following…
A: Given: PT=0.306 PTc=0.694 PC|T=0.391 PL|T=0.285
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A: The distribution of X is given Let us compute E(X2) E(X2)=∑xx2P(X=x)=(-2)2 P(X=-2)…
Q: information, (a)Are the events L and F mutually exclusive? (b)Are the events L and F independent?
A: It is given asP(L) = 0.58P(F) = 0.5P(L∩F) = 0.31
Q: Given that the switchboard of consultant's office receives on the average 0.9 calls per minute, find…
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Q: The probability of flu symptoms for a person not receiving any treatment is 0.036. In a clinical…
A: (a) The probability of flu symptoms is 0.036. The sample size is 858 which is larger indicating that…
Prior
Suppose P(B|A1)=0.20, P(B|A2)=0.05
P(B)=?
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- The probability of flu symptoms for a person not receiving any treatment is 0.033. In a clinical trial of a common drug used to lower cholesterol, 29 of 808 people treated experienced flu symptoms. Assuming the drug has no effect on the likelihood of flu symptoms, estimate the probability that at least 29 people experience flu symptoms. What do these results suggest about flu symptoms as an adverse reaction to the drug? (a) P(X2 29) = (Round to four decimal places as needed.)Given that the switchboard of consultant's office receives on the average 0.9 calls per minute, find the probabilities that: (a) In a given minute there will be at least one incoming all. (b) Between 10.00 a.m. and 10.02 a.m. there will be exactly 2 incoming calls. (c) During an interval lof 4 minutes there will be at most 3 incoming calls.What’s the answer of this
- Find the probability of the indicated event if P(E) = 0.25 and P(F) = 0.35. Find P(E or F) if P(E and F)= 0.20. P(E or F) =| (Simplify your answer.)Even with email, offices use a lot of paper. The manager of an office has estimated how many reams (packs of 500 sheets) are used each day and has assigned these probabilities. Use the table to complete parts a through e below. X= # of reams of paper used P(X = x) 1 2 3 0.05 0.30 0.30 0.15 0.05 0.15 ..... (a) How many reams should the manager expect to use each day? |reams (Round to two decimal places as needed.)The probability of flu symptoms for a person not receiving any treatment is 0.032. In a clinical trial of a common drug used to lower cholesterol, 39 of 1137 people treated experienced flu symptoms. Assuming the drug has no effect on the likelihood of flu symptoms, estimate the probability that at least 39 people experience flu symptoms. What do these results suggest about flu symptoms as an adverse reaction to the drug? (a). P(Xgreater than or equals 39)equals (Round to four decimal places as needed.)
- Rhett owns a cupcake bakery and is analyzing his sales of cupcake delivery orders. Based on his daily sales of delivery orders for the past month, he has already calculated the probabilities, ?(?),P(X), for the number of boxes of cupcakes, ?,X, purchased by a single customer in a single day, as shown in the table. ?X 1 2 3 4 5 ?(?)P(X) 0.75 0.05 0.10 0.05 0.05 Calculate the mean number of boxes of cupcakes, ??,μX, sold and delivered per person in a single day. Express your answer to two decimal places. ??=μX= If a box of cupcakes costs $40.00$40.00 and the flat-rate delivery fee is $7.00$7.00, calculate the mean sales per person, ??,μY, that the cupcake shop makes in a single day for delivery orders. Express your answer to the nearest cent. ??=$μY=$The probability of a dry summer is equal to 0.3, the probability of a wet summer is equal to 0.2, and the probability of a summer with normal precipitation is equal to 0.5. A climatologist observed the precipitation during three consecutive summers. Find the probabilities for the following scenarios. Show steps. (a) What is the probability of observing three normal summers? (b) What is the probability of observing two wet summers? (c) What is the probability of observing at least two wet summers?The prior probabilities for events A1, A2, and A3 are P(A1) = 0.20, P(A2) = 0.30, and P(A3) = 0.50. The conditional probabilities of event B given A1, A2, and A3 are P(B | A1) = 0.50, P(B | A2) = 0.30, and P(B | A3) = 0.40. (Assume that A1, A2, and A3 are mutually exclusive events whose union is the entire sample space.) (a) Compute P(B ∩ A1), P(B ∩ A2), and P(B ∩ A3). P(B ∩ A1) = P(B ∩ A2) = P(B ∩ A3) = (b) Apply Bayes' theorem, P(Ai | B) = P(Ai)P(B | Ai) P(A1)P(B | A1) + P(A2)P(B | A2) + + P(An)P(B | An) , to compute the posterior probability P(A2 | B). (Round your answer to two decimal places.) (c) Use the tabular approach to applying Bayes' theorem to compute P(A1 | B), P(A2 | B), and P(A3 | B). (Round your answers to two decimal places.) Events P(Ai) P(B | Ai) P(Ai ∩ B) P(Ai | B) A1 0.20 0.50 A2 0.30 0.30 A3 0.50 0.40 1.00 1.00
- A sample is selected from one of two populations, S, and S₂, with P(S₁) = 0.6 and P(S₂) = 0.4. The probabilities that an event A occurs, given that event S, or S₂ has occurred are P(A|S₂) = = 0.4 and P(AIS₂) = 0.3 and the probability of event A is P(A) = 0.36. Use Bayes' Rule to find P(S, IA). (Round your answer to four decimal places.)(a) What is the probability that a randomly selected worker primarily drives a bicycle or takes public transportation to work? P(worker drives a bicycle or takes public transportation to work) =| (Type an integer or decimal rounded to three decimal places as needed.) %3D (b) What is the probability that a randomly selected worker primarily neither drives a bicycle nor takes public transportation to work? P(worker neither drives a bicycle nor takes public transportation to work) = (Type an integer or decimal rounded to three decimal places as needed.) (c) What is the probability that a randomly selected worker primarily does not drive a bicycle to work? P(worker does not drive a bicycle to work) = %3D (Type an integer or decimal rounded to three decimal places as needed.)A manufacturer of plumbing fixtures has developed a new type of washerless faucet. Let p = P(a randomly selected faucet of this type will develop a leak within 2 years under normal use). The manufacturer has decided to proceed with production unless it can be determined that p is too large; the borderline acceptable value of p is specified as 0.10. The manufacturer decides to subject n of these faucets to accelerated testing (approximating 2 years of normal use). With X = the number among the n faucets that leak before the test concludes, production will commence unless the observed X is too large. It is decided that if p = 0.10, the probability of not proceeding should be at most 0.10, whereas if p = 0.30 the probability of proceeding should be at most 0.10. (Assume the rejection region takes the form reject H, if X 2 c for some c. Round your answers to three decimal places.) What are the error probabilities for n = 10? n USE SALT P-value = 0.07 B(0.3) =