decided to proceed with production unless it can be determined that p is too large; the borderline acceptable value of p is specified as 0.10. The manufacturer decides to subject n of these faucets to accelerated esting (approximating 2 years of normal use). With X = the number among the n faucets that leak before the test concludes, production will commence unless the observed X is too large. It is decided that if = 0.10, the probability of not proceeding should be at most 0.10, whereas if p = 0.30 the probability of proceeding should be at most 0.10. (Assume the rejection region takes the form reject Ho if X 2 cfor some . Round your answers to three decimal places.) What are the error probabilities for n = 10? n USE SALT P-value = 0.07
decided to proceed with production unless it can be determined that p is too large; the borderline acceptable value of p is specified as 0.10. The manufacturer decides to subject n of these faucets to accelerated esting (approximating 2 years of normal use). With X = the number among the n faucets that leak before the test concludes, production will commence unless the observed X is too large. It is decided that if = 0.10, the probability of not proceeding should be at most 0.10, whereas if p = 0.30 the probability of proceeding should be at most 0.10. (Assume the rejection region takes the form reject Ho if X 2 cfor some . Round your answers to three decimal places.) What are the error probabilities for n = 10? n USE SALT P-value = 0.07
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question

Transcribed Image Text:A manufacturer of plumbing fixtures has developed a new type of washerless faucet. Let p = P(a randomly selected faucet of this type will develop a leak within 2 years under normal use). The manufacturer has
decided to proceed with production unless it can be determined that p is too large; the borderline acceptable value of p is specified as 0.10. The manufacturer decides to subject n of these faucets to accelerated
testing (approximating 2 years of normal use). With X = the number among the n faucets that leak before the test concludes, production will commence unless the observed X is too large. It is decided that if
p = 0.10, the probability of not proceeding should be at most 0.10, whereas if p = 0.30 the probability of proceeding should be at most 0.10. (Assume the rejection region takes the form reject H, if X 2 c for some
c. Round your answers to three decimal places.)
What are the error probabilities for n = 10?
n USE SALT
P-value =
0.07
B(0.3) =

Transcribed Image Text:What are the error probabilities for n = 20?
P-value
0.043
B(0.3)
Can n = 20 be used?
O It is not possible to usen = 20 because there is no value of X which results in a P-value < 0.1.
It is not possible to use n = 20 because it results in B(0.3) > 0.1.
O It is not possible to use n = 20 because it results in B(0.3) < 0.1.
O It is possible to use n = 20 because both the P-value and B(0.3) are less than 0.1.
O It is possible to use n = 20 because both the P-value and B(0.3) are greater than 0.1.
What are the error probabilities for n = 25?
P-value =
0.098
B(0.3)
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