A random sample of size 64 is taken from a normal population having a mean of 70 and a standard deviation of 6. A second random sample of size 49 is taken from a different normal population having a mean of 60 and a standard deviation of 7. Find the probability that the sample mean computed from the 64 measurements will exceed the sample mean computed from the 49 measurements by at least 7.8 but less than 10.7. Assume the difference of the means to be measured to the nearest tenth. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. The probability is (Round to four decimal places as needed.)

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### Probability and Normal Distribution

A random sample of size 64 is taken from a normal population having a mean of 70 and a standard deviation of 6. A second random sample of size 49 is taken from a different normal population having a mean of 60 and a standard deviation of 7. Find the probability that the sample mean computed from the 64 measurements will exceed the sample mean computed from the 49 measurements by at least 7.8 but less than 10.7. Assume the difference of the means to be measured to the nearest tenth.

**Resources**:
- [Click here to view page 1 of the standard normal distribution table.](#)
- [Click here to view page 2 of the standard normal distribution table.](#)

#### Figure Illustration
There are no corresponding figures or graphs in this section. The scenario described involves comparing sample means from two different normal distributions and finding the probability within a specified range. 

To calculate this probability, one would generally use the properties of the sampling distribution of the difference of the sample means, followed by standardizing this difference to the standard normal distribution. The provided links lead to the standard normal distribution tables, which can be used to find the corresponding probabilities for the computed z-values.

**Required Calculation:**
The probability is \[\_\_\_\_\_\_\_\_ \].  
(Round to four decimal places as needed.)
Transcribed Image Text:### Probability and Normal Distribution A random sample of size 64 is taken from a normal population having a mean of 70 and a standard deviation of 6. A second random sample of size 49 is taken from a different normal population having a mean of 60 and a standard deviation of 7. Find the probability that the sample mean computed from the 64 measurements will exceed the sample mean computed from the 49 measurements by at least 7.8 but less than 10.7. Assume the difference of the means to be measured to the nearest tenth. **Resources**: - [Click here to view page 1 of the standard normal distribution table.](#) - [Click here to view page 2 of the standard normal distribution table.](#) #### Figure Illustration There are no corresponding figures or graphs in this section. The scenario described involves comparing sample means from two different normal distributions and finding the probability within a specified range. To calculate this probability, one would generally use the properties of the sampling distribution of the difference of the sample means, followed by standardizing this difference to the standard normal distribution. The provided links lead to the standard normal distribution tables, which can be used to find the corresponding probabilities for the computed z-values. **Required Calculation:** The probability is \[\_\_\_\_\_\_\_\_ \]. (Round to four decimal places as needed.)
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