Principle: lodometry The percentage purity of cupric sulfate set by the NF is 98.5 to 100.5% Procedure (reduce formulation to %, 1 trial only) 1. Weigh 650 mg of cupric sulfate (Cuso, · 5H;O) and dissolve in 50 ml of water. 2. Add 4 ml of acetic acid and 3 g of potassium iodide 3. Titrate the solution with 0.1 N sodium thiosulfate then adding 3 ml of starch TS as the end point is approached. 4. Perform a blank titration. (Blank titration is a solution containing all the reagents in the procedure except the analyte) 5. Calculate the percentage purity of the sample, using the formula: (mlgiana" mi) * N x meq 100 % % = Reaction (fillin the coefficients on the blank spaces): _CUSO4 5H2O + _ KI →_ Cul +_ 2 + _ K2SO4 + _ H2O and 2Nazs:Os + la → Na:S.Os + 2Nal Reduction: Oxidizing agent Cu*2 +. Cu* Oxidation: Reducing agent 211 - 12º + _ *- * Number of e- gain/loss of copper is ;which is the factor of cupric sulfate Data and Results Trial 1 Weight of cupriC sulfate Volume of blank 28.0 ml 15.1 ml Volume of titration/assay Percentage

Principle: lodometry The percentage purity of cupric sulfate set by the NF is 98.5 to 100.5% Procedure (reduce formulation to %, 1 trial only) 1. Weigh 650 mg of cupric sulfate (Cuso, · 5H;O) and dissolve in 50 ml of water. 2. Add 4 ml of acetic acid and 3 g of potassium iodide 3. Titrate the solution with 0.1 N sodium thiosulfate then adding 3 ml of starch TS as the end point is approached. 4. Perform a blank titration. (Blank titration is a solution containing all the reagents in the procedure except the analyte) 5. Calculate the percentage purity of the sample, using the formula: (mlgiana" mi) * N x meq 100 % % = Reaction (fillin the coefficients on the blank spaces): _CUSO4 5H2O + _ KI →_ Cul +_ 2 + _ K2SO4 + _ H2O and 2Nazs:Os + la → Na:S.Os + 2Nal Reduction: Oxidizing agent Cu2 +. Cu Oxidation: Reducing agent 211 - 12º + _ - Number of e- gain/loss of copper is ;which is the factor of cupric sulfate Data and Results Trial 1 Weight of cupriC sulfate Volume of blank 28.0 ml 15.1 ml Volume of titration/assay Percentage

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter10: Potentiometry And Redox Titrations

Section: Chapter Questions

Problem 8P

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Question

This is a practice problem.

Experiment 3. Assay of Cupric Sulfate
Principle:
lodometry
The percentage purity of cupric sulfate set by the NF is 98.5 to 100.5%
Procedure (reduce formulation to %, 1 trial only)
1. Weigh 650 mg of cupric sulfate (Cuso. 5H;O] and dissolve in 50 ml of water.
2. Add 4 ml of acetic acid and 3 g of potassium iodide
3. Titrate the solution with 0.1 N sodium thiosulfate then adding 3 ml of starch TS as the end point is approached.
4. Perform a blank titration. (Blank titration is a solution containing all the reagents in the procedure except the analyte)
5. Calculate the percentage purity of the sample, using the formula:
% = mlgiana mlaay)*Nx meg
x 100 %
wt
Reaction (fillin the coefficients on the blank spaces):
- CUSO4 5H2O +_ KI →_ Cul +_ 12 +,
K2SO4 +_ H2O
and 2NazS2Oa + l2 + Na:S«Os + 2Nal
Reduction: Oxidizing agent
Cu*2 +
e- - Cu1
Oxidation: Reducing agent 21-1 → 12° +
* Number of e- gain/loss of copper is
:which is the factor of cupric sulfate
Data and Results
Trial 1
Weight of cupric sulfate
Volume of blank
Volume of titration/assay
Percentage
28.0 ml
15.1 ml
Calculation and Conclusion
On space below, solve the titer value and percentage purity of the sample then interpret.

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