Prime Paints manufactures two types of paints, one for interior painting and the other for exterior painting. Both types require the use of two raw materials - M1 and M2, so that the maximum daily availabilities of these materials are 24 tons and 6 tons, respectively. It is known that 1 ton of the interior type of paint requires 4 tons of M1 and 2 tons of M2. On the other hand, 1 ton of the exterior type of paint requires 6 tons of M1 and 1 ton of M2. It has been established that the daily demand for interior paint cannot exceed that for the exterior paint by more than 1 ton. Also, the maximum daily demand for interior paint is 2 tons. The company wants to determine the optimum product mix of interior and exterior paints to maximize the total daily profit given that the profit per ton of the interior paint is 4 thousand dollars and the profit per ton of the exterior paint is 5 thousand dollars.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Prime Paints manufactures two types of
paints, one for interior painting and the
other for exterior painting. Both types
require the use of two raw materials -
M1 and M2, so that the maximum daily
availabilities of these materials are 24
tons and 6 tons, respectively. It is
known that 1 ton of the interior type of
paint requires 4 tons of M1 and 2 tons
of M2. On the other hand, 1 ton of the
exterior type of paint requires 6 tons of
M1 and 1 ton of M2. It has been
established that the daily demand for
interior paint cannot exceed that for the
exterior paint by more than 1 ton. Also,
the maximum daily demand for interior
paint is 2 tons. The company wants to
determine the optimum product mix of
interior and exterior paints to maximize
the total daily profit given that the profit
per ton of the interior paint is 4
thousand dollars and the profit per ton
of the exterior paint is 5 thousand
dollars.
Transcribed Image Text:Prime Paints manufactures two types of paints, one for interior painting and the other for exterior painting. Both types require the use of two raw materials - M1 and M2, so that the maximum daily availabilities of these materials are 24 tons and 6 tons, respectively. It is known that 1 ton of the interior type of paint requires 4 tons of M1 and 2 tons of M2. On the other hand, 1 ton of the exterior type of paint requires 6 tons of M1 and 1 ton of M2. It has been established that the daily demand for interior paint cannot exceed that for the exterior paint by more than 1 ton. Also, the maximum daily demand for interior paint is 2 tons. The company wants to determine the optimum product mix of interior and exterior paints to maximize the total daily profit given that the profit per ton of the interior paint is 4 thousand dollars and the profit per ton of the exterior paint is 5 thousand dollars.
exterior paint by more than 1 ton. Also,
the maximum daily demand for interior
paint is 2 tons. The company wants to
determine the optimum product mix of
interior and exterior paints to maximize
the total daily profit given that the profit
per ton of the interior paint is 4
thousand dollars and the profit per ton
of the exterior paint is 5 thousand
dollars.
Suppose x represents the number of
tons produced daily of interior paints
and y represents the number of tons
produced daily of exterior paints. Which
of the following is a feasible solution to
this problem?
Ox=2, y = 1
Ox= -2, y = 0
Ox= 3, y = 1
Ox=2, y = 3
Transcribed Image Text:exterior paint by more than 1 ton. Also, the maximum daily demand for interior paint is 2 tons. The company wants to determine the optimum product mix of interior and exterior paints to maximize the total daily profit given that the profit per ton of the interior paint is 4 thousand dollars and the profit per ton of the exterior paint is 5 thousand dollars. Suppose x represents the number of tons produced daily of interior paints and y represents the number of tons produced daily of exterior paints. Which of the following is a feasible solution to this problem? Ox=2, y = 1 Ox= -2, y = 0 Ox= 3, y = 1 Ox=2, y = 3
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