Prime Paints manufactures two types of paints, one for interior painting and the other for exterior painting. Both types require the use of two raw materials - M1 and M2, so that the maximum daily availabilities of these materials are 24 tons and 6 tons, respectively. It is known that 1 ton of the interior type of paint requires 4 tons of M1 and 2 tons of M2. On the other hand, 1 ton of the exterior type of paint requires 6 tons of M1 and 1 ton of M2. It has been established that the daily demand for interior paint cannot exceed that for the exterior paint by more than 1 ton. Also, the maximum daily demand for interior paint is 2 tons. The company wants to determine the optimum product mix of interior and exterior paints to maximize the total daily profit given that the profit per ton of the interior paint is 4 thousand dollars and the profit per ton of the exterior paint is 5 thousand dollars. Suppose x represents the number of tons produced daily of interior paints and y represents the number of tons produced daily of exterior paints. Which of the following is the optimal solution to this LP problem? (Refer to the feasible region shown below.) A = (0, 4) В - (1,5, 3) 3 C = (2, 2) D = (2, 1) 1 F = (0, 0) E = (1, 0) O a = 2, y = 1 O x = 1.5, y=3 O x = 1, y = 0 O x = 2, y = 2
Prime Paints manufactures two types of paints, one for interior painting and the other for exterior painting. Both types require the use of two raw materials - M1 and M2, so that the maximum daily availabilities of these materials are 24 tons and 6 tons, respectively. It is known that 1 ton of the interior type of paint requires 4 tons of M1 and 2 tons of M2. On the other hand, 1 ton of the exterior type of paint requires 6 tons of M1 and 1 ton of M2. It has been established that the daily demand for interior paint cannot exceed that for the exterior paint by more than 1 ton. Also, the maximum daily demand for interior paint is 2 tons. The company wants to determine the optimum product mix of interior and exterior paints to maximize the total daily profit given that the profit per ton of the interior paint is 4 thousand dollars and the profit per ton of the exterior paint is 5 thousand dollars. Suppose x represents the number of tons produced daily of interior paints and y represents the number of tons produced daily of exterior paints. Which of the following is the optimal solution to this LP problem? (Refer to the feasible region shown below.) A = (0, 4) В - (1,5, 3) 3 C = (2, 2) D = (2, 1) 1 F = (0, 0) E = (1, 0) O a = 2, y = 1 O x = 1.5, y=3 O x = 1, y = 0 O x = 2, y = 2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Prime Paints manufactures two types of paints, one for interior painting and the other for exterior painting. Both types require
the use of two raw materials - M1 and M2, so that the maximum daily availabilities of these materials are 24 tons and 6 tons,
respectively. It is known that 1 ton of the interior type of paint requires 4 tons of M1 and 2 tons of M2. On the other hand, 1 ton
of the exterior type of paint requires 6 tons of M1 and 1 ton of M2. It has been established that the daily demand for interior
paint cannot exceed that for the exterior paint by more than 1 ton. Also, the maximum daily demand for interior paint is 2 tons.
The company wants to determine the optimum product mix of interior and exterior paints to maximize the total daily profit given
that the profit per ton of the interior paint is 4 thousand dollars and the profit per ton of the exterior paint is 5 thousand dollars.
Suppose x represents the number of tons produced daily of interior paints and y represents the number of tons produced daily of
exterior paints. Which of the following is the optimal solution to this LP problem? (Refer to the feasible region shown below.)
A = (0, 4)
B = (1,5, 3)
3
C = (2, 2)
• D= (2, 1)
1
F = (0, 0)
E = (1, 0)
O x = 2, y = 1
O x = 1.5, y = 3
O x = 1, y = 0
O * = 2, y = 2
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