PreviousProblem ListNextIn order to compare the means of two populations, independent random samples of 237| observations are selected from each population, with the following results:Sample 1 Sample 221 12s1 = 130 s2175(a) .Use a 971 % confidence interval to estimate the difference between the population means (41 – H2)!(b) . Test the null hypothesis: Ho : (41 - 42) = 0 versus the alternative hypothesis: H. : (41 – 42) + 0|. Using a = 0.03 give the following:(i) , the test statistic z =(ii) .the positive critical 21 score(ii) . the negative critical 21scoreThe final conclustion isOA. We can reject the null hypothesis that (41 – 42) = 0 and accept that (1 – H2) + 0OB. There is not sufficient evidence to reject the null hypothesis that (1 - H2) = 0(c) . Test the null hypothesis: Ho : (u - 12) = 21| versus the alternative hypothesis: H, : (41 - 42) + 21. Using a = 0.03. give the following:(i) , the test statistic z =(ii) .the positive critical 2l score(ii) . the negative critical 21scoreThe final conclustion isOA. There is not sufficient evidence to reject the null hypothesis that (1 - 42) = 21OB. We can reject the null hypothesis that (41 – H2) = 21| and accept that (41 - 42) + 21

Given n1=n2=237 X1bar=1,X2bar=130 S1=175, S2=175

Previous Problem List Next In order to compare the means of two populations, independent random samples of 237l observations are selected from each population, with the following results: Sample 1 Sample 2 1 z2 = 2 130 s2 = 175 51 (a) .Use a 971 % confidence interval to estimate the difference between the population means (4 - 2) < (41 - 42) 4 (b) . Test the nul hypothesis: Ho : (41- H2) = 0 versus the alternative hypothesis: H. : (41 - Hz) + 0 Using a = 0.03 give the following: (1) .the test statistic z = (i) .the positive critical ascore (i) . the negative critical ascore. The final conclustion is OA. We can reject the null hypothesis that (41 - H2) = qand accept that (1 - H2) + 4 OB. There is not sufficient evidence to reject the null hypothesis that ( - pa) = 0 (c) , Test the null hypothesis: Ho : (41 – 2) = 21| versus the alternative hypothesis: H, : (41 - Hz) + 21| Using a = 0.01 give the following (1) .the test statistic z = (i) the positive critical ascore (i) . the negative critical Ascore. The final conclustion is OA. There is not sufficient evidence to reject the null hypothesis that (41 - 2) = 21 OB. We can reject the null hypothesis that (41 - H2) = 21|ļand accept that (41 - H2) + 21|

Previous Problem List Next In order to compare the means of two populations, independent random samples of 237l observations are selected from each population, with the following results: Sample 1 Sample 2 1 z2 = 2 130 s2 = 175 51 (a) .Use a 971 % confidence interval to estimate the difference between the population means (4 - 2) < (41 - 42) 4 (b) . Test the nul hypothesis: Ho : (41- H2) = 0 versus the alternative hypothesis: H. : (41 - Hz) + 0 Using a = 0.03 give the following: (1) .the test statistic z = (i) .the positive critical ascore (i) . the negative critical ascore. The final conclustion is OA. We can reject the null hypothesis that (41 - H2) = qand accept that (1 - H2) + 4 OB. There is not sufficient evidence to reject the null hypothesis that ( - pa) = 0 (c) , Test the null hypothesis: Ho : (41 – 2) = 21| versus the alternative hypothesis: H, : (41 - Hz) + 21| Using a = 0.01 give the following (1) .the test statistic z = (i) the positive critical ascore (i) . the negative critical Ascore. The final conclustion is OA. There is not sufficient evidence to reject the null hypothesis that (41 - 2) = 21 OB. We can reject the null hypothesis that (41 - H2) = 21|ļand accept that (41 - H2) + 21|

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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