Pressurized tank delivering a vertical jet. Compute the required air pressure above the water to cause the jet to rise 40.0 ft from the nozzle. The depth h = 6.0 ft. HINT Use Bernoulli's equation successively between points 1 and 2; 2 and 3; 1 and 3. P,ly + Z, + V,?/2g = P,/ y + Z, + V,2/2g 40.0 f1 P/y + Zz + V,2/2g = P,/ y + Z3 + V,/2g Air pressare P,ly + Z, + V,?/2g = P,/ y + Z3 + V,2/2g h- 6.0 ft Use Ref. Level
Pressurized tank delivering a vertical jet. Compute the required air pressure above the water to cause the jet to rise 40.0 ft from the nozzle. The depth h = 6.0 ft. HINT Use Bernoulli's equation successively between points 1 and 2; 2 and 3; 1 and 3. P,ly + Z, + V,?/2g = P,/ y + Z, + V,2/2g 40.0 f1 P/y + Zz + V,2/2g = P,/ y + Z3 + V,/2g Air pressare P,ly + Z, + V,?/2g = P,/ y + Z3 + V,2/2g h- 6.0 ft Use Ref. Level
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![**Title: Calculating Air Pressure for a Vertical Water Jet**
**Overview:**
A pressurized tank delivers water as a vertical jet. The objective is to compute the necessary air pressure above the water to make the jet rise to a height of 40.0 ft from the nozzle. The water depth in the tank is given as \( h = 6.0 \, \text{ft} \).
**Instructions:**
Apply Bernoulli's equation successively between the following points:
1. Points 1 and 2
2. Points 2 and 3
3. Points 1 and 3
### Bernoulli's Equations:
#### Between Points 1 and 2:
\[
\frac{P_1}{\gamma} + Z_1 + \frac{V_1^2}{2g} = \frac{P_2}{\gamma} + Z_2 + \frac{V_2^2}{2g}
\]
#### Between Points 2 and 3:
\[
\frac{P_2}{\gamma} + Z_2 + \frac{V_2^2}{2g} = \frac{P_3}{\gamma} + Z_3 + \frac{V_3^2}{2g}
\]
#### Between Points 1 and 3:
\[
\frac{P_1}{\gamma} + Z_1 + \frac{V_1^2}{2g} = \frac{P_3}{\gamma} + Z_3 + \frac{V_3^2}{2g}
\]
**Diagram Explanation:**
- The diagram shows a pressurized tank with water and a vertical pipe.
- The water level is marked at a depth of 6.0 ft.
- The air pressure is exerted over the water surface.
- The vertical jet rises to 40.0 ft above the nozzle, labeled as Point 3.
- Reference levels are marked for clarity.
**Key Terms:**
- \( P \): Pressure at each point
- \( \gamma \): Specific weight of the fluid
- \( Z \): Elevation head
- \( V \): Velocity
- \( g \): Acceleration due to gravity
Use these equations and the diagram to solve for the required air pressure to achieve the desired jet height.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F535a6610-5408-42b9-810f-cca1f66cb656%2F51caecee-88fc-4d63-b5f3-daeabf0020ba%2Fv76n81o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Calculating Air Pressure for a Vertical Water Jet**
**Overview:**
A pressurized tank delivers water as a vertical jet. The objective is to compute the necessary air pressure above the water to make the jet rise to a height of 40.0 ft from the nozzle. The water depth in the tank is given as \( h = 6.0 \, \text{ft} \).
**Instructions:**
Apply Bernoulli's equation successively between the following points:
1. Points 1 and 2
2. Points 2 and 3
3. Points 1 and 3
### Bernoulli's Equations:
#### Between Points 1 and 2:
\[
\frac{P_1}{\gamma} + Z_1 + \frac{V_1^2}{2g} = \frac{P_2}{\gamma} + Z_2 + \frac{V_2^2}{2g}
\]
#### Between Points 2 and 3:
\[
\frac{P_2}{\gamma} + Z_2 + \frac{V_2^2}{2g} = \frac{P_3}{\gamma} + Z_3 + \frac{V_3^2}{2g}
\]
#### Between Points 1 and 3:
\[
\frac{P_1}{\gamma} + Z_1 + \frac{V_1^2}{2g} = \frac{P_3}{\gamma} + Z_3 + \frac{V_3^2}{2g}
\]
**Diagram Explanation:**
- The diagram shows a pressurized tank with water and a vertical pipe.
- The water level is marked at a depth of 6.0 ft.
- The air pressure is exerted over the water surface.
- The vertical jet rises to 40.0 ft above the nozzle, labeled as Point 3.
- Reference levels are marked for clarity.
**Key Terms:**
- \( P \): Pressure at each point
- \( \gamma \): Specific weight of the fluid
- \( Z \): Elevation head
- \( V \): Velocity
- \( g \): Acceleration due to gravity
Use these equations and the diagram to solve for the required air pressure to achieve the desired jet height.
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