Pressure and temperature affect the amount of space between gas molecules, which affects the volume and, therefore, the density of the gas since density= The molar mass of a substance, however, is a constant and can be used to identify an unknown gas sample. Molar mass is found by dividing the mass of a sample (in grams) by the number of moles in that sample. The number of moles of gas can be calculated using the ideal gas law PV = nRT which can be rearranged as n= Given the number of moles of a gas and its molar mass, you can calculate the mass of the gas. Since density is equal to the ratio of the mass and volume, you can then dhide by the volume to find density Alternatively, you can use the ratio n/V from the ideal gas equation where is the number of moles and V is the volume, and convert from moles per unit volume to grams per unit volume using molar mass Part A Calculate the density of oxygen, O₂, under each of the following conditions: .STP 1.00 atm and 350 C Express your answers numerically in grams per liter to three significant figures. Enter the density at STP first and separate your answers by a comma. View Available Hint(s) density at STP density at 1 atm and 35.0 "C-0.142,1.3 Submit * Incorrect; Try Again Part B Previous Answers AE ? AZ -ΧΕΙ ΑΣΦ + + O? To identify a diatomic gas (X₂), a researcher canried out the following experiment: She weighed an empty 1.7-L bulb, then filled it with the gas at 1.80 atm and 29.0 "C and weighed it again. The difference in mass was 3.5 g. Identify the gas. Express your answer as a chemical formula. View Available Hints) noreaction A chemical reaction does not occur for this question Submit Previous Answers * Incorrect; Try Again Provide Feedback e/L Review

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help with part A and B in chemistry

 

**Gas Density and Molar Mass**

Pressure and temperature affect the amount of space between gas molecules, which affects the volume and, therefore, the density of the gas since:

\[ \text{density} = \frac{\text{mass}}{\text{volume}} \]

The molar mass of a substance, however, is a constant and can be used to identify an unknown gas sample. Molar mass is found by dividing the mass of a sample (in grams) by the number of moles in that sample. The number of moles of gas can be calculated using the ideal gas law:

\[ PV = nRT \]

which can be rearranged as:

\[ n = \frac{PV}{RT} \]

Given the number of moles of a gas and its molar mass, you can calculate the mass of the gas. Since density is equal to the ratio of the mass and volume, you can then divide by the volume to find density.

Alternatively, you can use the ratio n/V from the ideal gas equation where n is the number of moles and V is the volume, and convert from moles per unit volume to grams per unit volume using molar mass.

---

### Part A

Calculate the density of oxygen, \(\text{O}_2\), under each of the following conditions:

- STP
- \(1.00 \, \text{atm}\) and \(35.0 \, ^\circ\text{C}\)

Express your answers numerically in grams per liter to three significant figures. Enter the density at STP first and separate your answers by a comma.

**Input:**
- Density at STP, density at 1 atm and \(35 \, ^\circ\text{C}\): \(0.\mathbf{142},1.3 \, \text{g/L}\)

**Feedback:**
- Incorrect; Try Again

---

### Part B

To identify a diatomic gas (\(X_2\)), a researcher carried out the following experiment: She weighed an empty \(1.7\text{L}\) bulb, then filled it with the gas at \(1.80 \, \text{atm}\) and \(29.0 \, ^\circ\text{C}\) and weighed it again. The difference in mass was \(3.5 \, \text{g}\). Identify the gas.

**Feedback:**
- A chemical reaction
Transcribed Image Text:**Gas Density and Molar Mass** Pressure and temperature affect the amount of space between gas molecules, which affects the volume and, therefore, the density of the gas since: \[ \text{density} = \frac{\text{mass}}{\text{volume}} \] The molar mass of a substance, however, is a constant and can be used to identify an unknown gas sample. Molar mass is found by dividing the mass of a sample (in grams) by the number of moles in that sample. The number of moles of gas can be calculated using the ideal gas law: \[ PV = nRT \] which can be rearranged as: \[ n = \frac{PV}{RT} \] Given the number of moles of a gas and its molar mass, you can calculate the mass of the gas. Since density is equal to the ratio of the mass and volume, you can then divide by the volume to find density. Alternatively, you can use the ratio n/V from the ideal gas equation where n is the number of moles and V is the volume, and convert from moles per unit volume to grams per unit volume using molar mass. --- ### Part A Calculate the density of oxygen, \(\text{O}_2\), under each of the following conditions: - STP - \(1.00 \, \text{atm}\) and \(35.0 \, ^\circ\text{C}\) Express your answers numerically in grams per liter to three significant figures. Enter the density at STP first and separate your answers by a comma. **Input:** - Density at STP, density at 1 atm and \(35 \, ^\circ\text{C}\): \(0.\mathbf{142},1.3 \, \text{g/L}\) **Feedback:** - Incorrect; Try Again --- ### Part B To identify a diatomic gas (\(X_2\)), a researcher carried out the following experiment: She weighed an empty \(1.7\text{L}\) bulb, then filled it with the gas at \(1.80 \, \text{atm}\) and \(29.0 \, ^\circ\text{C}\) and weighed it again. The difference in mass was \(3.5 \, \text{g}\). Identify the gas. **Feedback:** - A chemical reaction
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