Preparation of 0.25N HCl Objective: Apparatus and Materials: Procedure: Compute for the volume of HCl needed to prepare 0L of 0.25N HCl. Using a graduated cylinder, measure the computed volume of HCl. Pour it into the volumetric flask that is half- filled with distilled water and agitate. Add enough distilled water until it reaches the mark. Transfer the solution to the reagent bottle. Add again distilled water until it reaches the mark and pour it to the same reagent bottle, thus making the total volume of 1.0L. Label the reagent bottle. Data and Computations: Conclusion:
Preparation of 0.25N HCl Objective: Apparatus and Materials: Procedure: Compute for the volume of HCl needed to prepare 0L of 0.25N HCl. Using a graduated cylinder, measure the computed volume of HCl. Pour it into the volumetric flask that is half- filled with distilled water and agitate. Add enough distilled water until it reaches the mark. Transfer the solution to the reagent bottle. Add again distilled water until it reaches the mark and pour it to the same reagent bottle, thus making the total volume of 1.0L. Label the reagent bottle. Data and Computations: Conclusion:
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.9QE
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Question
Preparation of 0.25N HCl
- Objective:
- Apparatus and Materials:
- Procedure:
- Compute for the volume of HCl needed to prepare 0L of 0.25N HCl.
- Using a graduated cylinder, measure the computed volume of HCl.
- Pour it into the volumetric flask that is half- filled with distilled water and agitate.
- Add enough distilled water until it reaches the mark.
- Transfer the solution to the reagent bottle.
- Add again distilled water until it reaches the mark and pour it to the same reagent bottle, thus making the total volume of 1.0L.
- Label the reagent bottle.
Data and Computations:
Conclusion:
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