Prelab Assignment: a) Balance the reaction below: BT2 ΔΗ'--100.18 kJ + b) How much energy will given off when off when 0.0664-g of bromine if formed? c) How many grams of chlorine gas will be needed to produce 80.5kJ? Use the thermochemical equations shown below to determine the enthalpy for the reaction: P4(s) + 6C12(g)--4PC13(g) 2. 4 PCIs(g)- P4(s) + 10 Cl2(g) PCI3(g) + Cl2(g) → PC15(g) H-1528KJ H=-111KJ
Prelab Assignment: a) Balance the reaction below: BT2 ΔΗ'--100.18 kJ + b) How much energy will given off when off when 0.0664-g of bromine if formed? c) How many grams of chlorine gas will be needed to produce 80.5kJ? Use the thermochemical equations shown below to determine the enthalpy for the reaction: P4(s) + 6C12(g)--4PC13(g) 2. 4 PCIs(g)- P4(s) + 10 Cl2(g) PCI3(g) + Cl2(g) → PC15(g) H-1528KJ H=-111KJ
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:Prelab Assignment:
a) Balance the reaction below:
BT2
ΔΗ'--100.18 kJ
+
b) How much energy will given off when off when 0.0664-g of bromine if formed?
c) How many grams of chlorine gas will be needed to produce 80.5kJ?
Use the thermochemical equations shown below to determine the enthalpy for the
reaction: P4(s) + 6C12(g)--4PC13(g)
2.
4 PCIs(g)- P4(s) + 10 Cl2(g)
PCI3(g) + Cl2(g) → PC15(g)
H-1528KJ
H=-111KJ
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