Predict the sign of AS for the following reaction Br O negative O No answer text provided. O no change O positive + HBr

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**Predicting the Sign of ΔS for a Given Reaction**

The image presents a chemical reaction for which you need to predict the sign of the change in entropy (ΔS).

**Reaction:**
\[ \text{C-Br} \quad \rightarrow \quad \text{C} = \text{C} + \text{HBr} \]

Here, a carbon-bromine compound reacts to form a carbon-carbon double bond (alkene) and hydrogen bromide (HBr).

**Options:**

1. Negative
2. No answer text provided.
3. No change
4. Positive

**Explanation of Reaction:**

In this reaction:
- On the left side, there is a single reactant molecule, the carbon-bromine (C-Br) compound.
- On the right side, there are two products: one molecule of alkene (carbon-carbon double bond) and one molecule of hydrogen bromide (HBr).

**Interpreting Entropy (ΔS):**

Entropy (S) is a measure of the disorder or randomness in a system:
- The formation of more products generally increases the entropy because more molecules usually mean more ways to arrange them and thereby more disorder/ randomness.
- Here, going from one reactant molecule to two product molecules suggests an increase in disorder.

Thus, the correct answer is likely to be **positive ΔS**, indicating an increase in entropy.

**Conclusion:**

Given the reaction and the options provided, you would predict the sign of ΔS to be positive. This reflects an increase in entropy as a result of the reaction producing more molecules.

**Quiz Question:**

Predict the sign of ΔS for the following reaction:

\[ \text{C-Br} \quad \rightarrow \quad \text{C} = \text{C} + \text{HBr} \]

- \( \bigcirc \) negative
- \( \bigcirc \) No answer text provided.
- \( \bigcirc \) no change
- \( \bigcirc \) positive
Transcribed Image Text:**Predicting the Sign of ΔS for a Given Reaction** The image presents a chemical reaction for which you need to predict the sign of the change in entropy (ΔS). **Reaction:** \[ \text{C-Br} \quad \rightarrow \quad \text{C} = \text{C} + \text{HBr} \] Here, a carbon-bromine compound reacts to form a carbon-carbon double bond (alkene) and hydrogen bromide (HBr). **Options:** 1. Negative 2. No answer text provided. 3. No change 4. Positive **Explanation of Reaction:** In this reaction: - On the left side, there is a single reactant molecule, the carbon-bromine (C-Br) compound. - On the right side, there are two products: one molecule of alkene (carbon-carbon double bond) and one molecule of hydrogen bromide (HBr). **Interpreting Entropy (ΔS):** Entropy (S) is a measure of the disorder or randomness in a system: - The formation of more products generally increases the entropy because more molecules usually mean more ways to arrange them and thereby more disorder/ randomness. - Here, going from one reactant molecule to two product molecules suggests an increase in disorder. Thus, the correct answer is likely to be **positive ΔS**, indicating an increase in entropy. **Conclusion:** Given the reaction and the options provided, you would predict the sign of ΔS to be positive. This reflects an increase in entropy as a result of the reaction producing more molecules. **Quiz Question:** Predict the sign of ΔS for the following reaction: \[ \text{C-Br} \quad \rightarrow \quad \text{C} = \text{C} + \text{HBr} \] - \( \bigcirc \) negative - \( \bigcirc \) No answer text provided. - \( \bigcirc \) no change - \( \bigcirc \) positive
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