Predict the products of each reaction below. Indicate regiochemistry and stereochemistry when relevant. e 1. Hg(OAC)2, H₂O 2. NaBH4

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Question 10
**Exercise: Predicting Reaction Products**
---

**Task:**
Predict the products of each reaction below. Indicate regiochemistry and stereochemistry when relevant.

**Reaction:**
\[ \text{Reactant:} \]

(The reactant is a compound containing a double bond between a carbon atom bonded to a methyl group (CH₃) and another carbon atom.)

\[
\begin{array}{c}
1. \text{Hg(OAc)}_2, \text{H}_2\text{O} \\
2. \text{NaBH}_4
\end{array}
\]

---

**Explanation:**
The provided reaction involves the addition of mercuric acetate (Hg(OAc)₂) in the presence of water (H₂O), followed by reduction with sodium borohydride (NaBH₄). This is a common method for converting alkenes into alcohols, specifically known as oxymercuration-demercuration.

1. **Oxymercuration**: The double bond reacts with mercuric acetate and water to form a mercurinium ion intermediate. This intermediate then undergoes nucleophilic attack by water, leading to the formation of an organomercury compound.

2. **Demercuration**: The organomercury compound is then reduced by sodium borohydride (NaBH₄), replacing the mercury with a hydrogen atom, resulting in the formation of an alcohol.

**Product:**
The product of this reaction will be an alcohol where the hydroxyl group (OH) is added to the more substituted carbon in the double bond, following Markovnikov's rule.

**Regiochemistry:**
The reaction adheres to Markovnikov’s rule, where the hydroxyl group attaches to the more substituted carbon atom of the original double bond.

**Stereochemistry:**
The resulting product does not have stereochemical constraints as the addition of Hg(OAc)₂ and the subsequent reduction with NaBH₄ typically lead to racemic mixtures if stereocenters are formed.

End of Exercise.

---

This explanation provides students with a clear understanding of the reaction process, the intermediate steps, and the resulting products, emphasizing the importance of regiochemistry and stereochemistry in organic synthesis.
Transcribed Image Text:**Exercise: Predicting Reaction Products** --- **Task:** Predict the products of each reaction below. Indicate regiochemistry and stereochemistry when relevant. **Reaction:** \[ \text{Reactant:} \] (The reactant is a compound containing a double bond between a carbon atom bonded to a methyl group (CH₃) and another carbon atom.) \[ \begin{array}{c} 1. \text{Hg(OAc)}_2, \text{H}_2\text{O} \\ 2. \text{NaBH}_4 \end{array} \] --- **Explanation:** The provided reaction involves the addition of mercuric acetate (Hg(OAc)₂) in the presence of water (H₂O), followed by reduction with sodium borohydride (NaBH₄). This is a common method for converting alkenes into alcohols, specifically known as oxymercuration-demercuration. 1. **Oxymercuration**: The double bond reacts with mercuric acetate and water to form a mercurinium ion intermediate. This intermediate then undergoes nucleophilic attack by water, leading to the formation of an organomercury compound. 2. **Demercuration**: The organomercury compound is then reduced by sodium borohydride (NaBH₄), replacing the mercury with a hydrogen atom, resulting in the formation of an alcohol. **Product:** The product of this reaction will be an alcohol where the hydroxyl group (OH) is added to the more substituted carbon in the double bond, following Markovnikov's rule. **Regiochemistry:** The reaction adheres to Markovnikov’s rule, where the hydroxyl group attaches to the more substituted carbon atom of the original double bond. **Stereochemistry:** The resulting product does not have stereochemical constraints as the addition of Hg(OAc)₂ and the subsequent reduction with NaBH₄ typically lead to racemic mixtures if stereocenters are formed. End of Exercise. --- This explanation provides students with a clear understanding of the reaction process, the intermediate steps, and the resulting products, emphasizing the importance of regiochemistry and stereochemistry in organic synthesis.
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