Predict the products for the following reaction (ignore balancing):O Sn3(PO4)2 (aq) + KNO3(aq)O Sn3(PO4)4 (s) + K (s) + NO₂(g)O No reactionO SnPO4 (s) + KNO3(aq)O Sn3(PO4)2 (s) + KNO3(aq)Consider the combustion of octane (C8H18), given the following unbalanced equation:O 227 gtin(II) nitrate (aq) + potassium phosphate (aq)O 4.54 gO 226 gO 79.8 gO 45.4 gC8H18 +O2 →What is the mass of H₂O (MM = 18.02 g/mol) will be generated by the complete combustion of 159.7 g of octane in excess oxygen?CO₂ +H₂O [unbalanced]6.66.67 3Convert 98.67 gal/m² to mL/pm².O 3.735 x 10-7 mL/pm²23.735 x 10-25 mL/pm²O 3.735 x 10-1⁹ mL/pm²O 2.607 x 10-20 mL/pm²2.607 x 10-25 mL/pm²

Here we have to predict the products formed in the following given reaction and moles of water…

Predict the products for the following reaction (ignore balancing): O Sna(PO4)2 (aq) + KNO3(aq) O Sny(PO4) (s) + K(s) + NO₂ (s) No reaction O SnPO, (s) + KNO3(aq) O Sn3(PO4)2 (s) + KNO3(aq) Consider the combustion of octane (CgH18). given the following unbalanced equation: tin(II) nitrate (aq) + potassium phosphate (aq) --> 227 g 4.54 g O226 g O 79.8 g O 454 g 000 C8H18 + 0₂ → CO₂ What is the mass of H₂O (MM = 18.02 g/mol) will be generated by the complete combustion of 159.7 g of octane in excess oxygen? H₂O [unbalanced]

Predict the products for the following reaction (ignore balancing): O Sna(PO4)2 (aq) + KNO3(aq) O Sny(PO4) (s) + K(s) + NO₂ (s) No reaction O SnPO, (s) + KNO3(aq) O Sn3(PO4)2 (s) + KNO3(aq) Consider the combustion of octane (CgH18). given the following unbalanced equation: tin(II) nitrate (aq) + potassium phosphate (aq) --> 227 g 4.54 g O226 g O 79.8 g O 454 g 000 C8H18 + 0₂ → CO₂ What is the mass of H₂O (MM = 18.02 g/mol) will be generated by the complete combustion of 159.7 g of octane in excess oxygen? H₂O [unbalanced]

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter4: Stoichiometry

Section: Chapter Questions

Problem 4.87PAE

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