Chlorine is used by textile manufacturers to bleach cloth. Excess chlorine is destroyed by its reaction with sodium thiosulfate, Na2S2O3, as follows:Na2S2O3(aq) + 4Cl2(g) + 5H2O 2NaHSO4(aq) + 8HCl(aq) Using the concepts established in the previous parts, answer the following questions about the following reaction:The octane in gasoline burns according to the following equation:2C8H18 + 25O2 → 16CO2 + 18H2O(a) How many moles of O2 are needed to react fully with 6.84 mol of octane? (b) How many moles of CO2 can form from 0.511 mol of octane? (c) How many moles of water are produced by the combustion of 8.20 mol of octane? (d) If this reaction is used to synthesize 6.00 mol of CO2, how many moles of oxygen are needed? How many moles of octane are needed? ? mol O2 ? mol C8H18 Thanks.

This question can be solved using law of multiple proportions:

Answered: hlorine is used by textile…

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter10: Gases And Their Properties

Section: Chapter Questions

Problem 100IL: You are given a solid mixture of NaNO2 and NaCl and are asked to analyze it for the amount of NaNO2...

See similar textbooks

Related questions

Question

Chlorine is used by textile manufacturers to bleach cloth. Excess chlorine is destroyed by its reaction with sodium thiosulfate, Na₂S₂O₃, as follows:

Na₂S₂O₃(aq) + 4Cl₂(g) + 5H₂O 2NaHSO₄(aq) + 8HCl(aq)

Using the concepts established in the previous parts, answer the following questions about the following reaction:

The octane in gasoline burns according to the following equation:

2C₈H₁₈ + 25O₂ → 16CO₂+ 18H₂O

(a) How many moles of O₂ are needed to react fully with 6.84 mol of octane?

(b) How many moles of CO₂ can form from 0.511 mol of octane?

(d) If this reaction is used to synthesize 6.00 mol of CO₂, how many moles of oxygen are needed? How many moles of octane are needed?

? mol O₂

? mol C₈H₁₈

_Thanks.

Expert Solution