Predict the immediate product. of each of the following Lewis Acid-Base reactions. CH3 - 0 - CH, + BF, → a. b. H-O - CH2-CH2 - CH2 - CH2 - CH - CH3 →

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**Predict the Immediate Product of the Following Lewis Acid-Base Reactions**

This exercise involves predicting the immediate product of two Lewis acid-base reactions. In each reaction, the Lewis base is identified by the presence of a lone pair of electrons, and the Lewis acid is the species that accepts the electron pair.

**a. Reaction 1:**
- Reactants: 
  - \( \text{CH}_3 - \overset{\cdot\cdot}{\text{O}}^– - \text{CH}_3 \) 
  - \( \text{BF}_3 \)

In this reaction, the methoxide ion acts as a Lewis base with its lone pair of electrons on the oxygen atom, and boron trifluoride (\( \text{BF}_3 \)) acts as a Lewis acid due to the electron-deficient boron atom. The immediate product is the adduct formed when the lone pair from the oxygen of methoxide interacts with the boron atom of \( \text{BF}_3 \).

**b. Reaction 2:**
- Reactants:
  - \( \text{H} - \overset{\cdot\cdot}{\text{O}} - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{CH} - \text{CH}_3 \)

In this case, the reactants indicate a linear chain alcohol with a hydroxyl group (\( \text{OH} \)) at one end. The oxygen atom with its lone pairs of electrons acts as a Lewis base. 

The other reactant is not shown but should involve a Lewis acid. The oxygen's lone pair can interact with an available electron-deficient atom in the missing reactant to create the immediate product.

**Note:** In both reactions, it is essential to identify which atoms act as electron donors and acceptors to predict the formation of the adducts. Understanding the nature of each reactant helps clarify their interaction in forming specific products in Lewis acid-base reactions.
Transcribed Image Text:**Predict the Immediate Product of the Following Lewis Acid-Base Reactions** This exercise involves predicting the immediate product of two Lewis acid-base reactions. In each reaction, the Lewis base is identified by the presence of a lone pair of electrons, and the Lewis acid is the species that accepts the electron pair. **a. Reaction 1:** - Reactants: - \( \text{CH}_3 - \overset{\cdot\cdot}{\text{O}}^– - \text{CH}_3 \) - \( \text{BF}_3 \) In this reaction, the methoxide ion acts as a Lewis base with its lone pair of electrons on the oxygen atom, and boron trifluoride (\( \text{BF}_3 \)) acts as a Lewis acid due to the electron-deficient boron atom. The immediate product is the adduct formed when the lone pair from the oxygen of methoxide interacts with the boron atom of \( \text{BF}_3 \). **b. Reaction 2:** - Reactants: - \( \text{H} - \overset{\cdot\cdot}{\text{O}} - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{CH} - \text{CH}_3 \) In this case, the reactants indicate a linear chain alcohol with a hydroxyl group (\( \text{OH} \)) at one end. The oxygen atom with its lone pairs of electrons acts as a Lewis base. The other reactant is not shown but should involve a Lewis acid. The oxygen's lone pair can interact with an available electron-deficient atom in the missing reactant to create the immediate product. **Note:** In both reactions, it is essential to identify which atoms act as electron donors and acceptors to predict the formation of the adducts. Understanding the nature of each reactant helps clarify their interaction in forming specific products in Lewis acid-base reactions.
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