Predict the equilibrium concentration of O₂ in the reaction described below by constructing an equilibrium expression for Qc, constructing an ICE table, writing an equilibrium expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-4 before submitting your answer. N₂(g) + O₂(g) = 2 NO(g) Question 4 of 7 2 Qc = 3 NEXT > In a 1.0 L container at high temperature, 0.20 mol N₂ and 0.15 mol O₂ are allowed to react. Set up the expression for Qc. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Qc to determine the direction of the reaction. 4 =

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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Predict the equilibrium concentration of O₂ in the reaction described below by
constructing an equilibrium expression for Qc, constructing an ICE table,
writing an equilibrium expression for Kc, and solving for the equilibrium
concentration. Complete Parts 1-4 before submitting your answer.
N₂(g) + O₂(g) = 2 NO(g)
[0]
[0.050]
NEXT >
In a 1.0 L container at high temperature, 0.20 mol N₂ and 0.15 mol O₂ are allowed to react. Set
up the expression for Qc. Each reaction participant must be represented by one tile. Do not
combine terms.
Once the expression is constructed, solve for Qc to determine the direction of the reaction.
0.030
#
3
[1.0]
[0.20]²
9.0 x 10-4
1
$
4
Qc
=
[0]²
[0.15]²
1.1 x 10²
25
2
%
Question 4 of 7
[1.0]²
...
[0.40]²
^
6
3
[0.20]
[0.30]²
&
7
=
*
[0.15]
[0.050]²
8
4
(
9
[0.40]
0
)
RESET
[0.30]
33
+
Transcribed Image Text:mal resources @ 2 Predict the equilibrium concentration of O₂ in the reaction described below by constructing an equilibrium expression for Qc, constructing an ICE table, writing an equilibrium expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-4 before submitting your answer. N₂(g) + O₂(g) = 2 NO(g) [0] [0.050] NEXT > In a 1.0 L container at high temperature, 0.20 mol N₂ and 0.15 mol O₂ are allowed to react. Set up the expression for Qc. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Qc to determine the direction of the reaction. 0.030 # 3 [1.0] [0.20]² 9.0 x 10-4 1 $ 4 Qc = [0]² [0.15]² 1.1 x 10² 25 2 % Question 4 of 7 [1.0]² ... [0.40]² ^ 6 3 [0.20] [0.30]² & 7 = * [0.15] [0.050]² 8 4 ( 9 [0.40] 0 ) RESET [0.30] 33 +
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