practice. This function returns the updated number after the nTimes number of iterations. It also displays the rotated number for each iteration. (Note that for each iteration, the leftmost digit becomes the the rightmost digit.) For example, if num is 456 and nTimes is 1, the function displays - 1: 564 and returns 564. Another example is if num is 709134 and nTimes is 3, the function displays *- 1: 91347, 2: 913470 , 3: 134709 and returns 134709. * @param num the original number to be rotated * @param nTimes the number times num will be rotated to the left * @return rotated the number // The Real Function// */ int rotateLeft(int num, int nTimes) { }
Using C not(C++ or C#) without the use of strings and arrays, I need help in coding this small function as part of practice.
This function returns the updated number after the nTimes number of iterations. It also displays the rotated number for each iteration. (Note that for each iteration, the leftmost digit becomes the the rightmost digit.)
For example, if num is 456 and nTimes is 1, the function displays - 1: 564 and returns 564.
Another example is if num is 709134 and nTimes is 3, the function displays *- 1: 91347, 2: 913470 , 3: 134709 and returns 134709.
* @param num the original number to be rotated
* @param nTimes the number times num will be rotated to the left * @return rotated the number
// The Real Function//
*/ int rotateLeft(int num, int nTimes) {
}
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