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PRACTICE In the circuit of Fig. 2.12b, vs1 = 120 V, v52 = 30 V, R1 = 30 2, and R2 = 15 N. Compute the power absorbed by each element. %3D Ans: P120v = -240 W; P30v = +60 W; P302 = 120 W; Pi59 = 60 W. R, R2 (b)

PRACTICE In the circuit of Fig. 2.12b, vs1 = 120 V, v52 = 30 V, R1 = 30 2, and R2 = 15 N. Compute the power absorbed by each element. %3D Ans: P120v = -240 W; P30v = +60 W; P302 = 120 W; Pi59 = 60 W. R, R2 (b)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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PRACTICE In the circuit of Fig. 2.12b, vs1 = 120 V, v;2 = 30 V, RỊ = 30 2, and R2 = 15 2. Compute the power absorbed by each element. Ans: P120v = -240 W; P30v = +60 W; P302 = 120 W; p152 = 60 W. R2 (b)
Transcribed Image Text:PRACTICE In the circuit of Fig. 2.12b, vs1 = 120 V, v;2 = 30 V, RỊ = 30 2, and R2 = 15 2. Compute the power absorbed by each element. Ans: P120v = -240 W; P30v = +60 W; P302 = 120 W; p152 = 60 W. R2 (b)
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