PRACTICE 7.5 What is the mass of 0.150 mol of Na SO4? PRACTICE 7.6 How many moles and molecules are there in 500.0 g of HC2H3O2?

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### Practice Questions for Chemistry Students

#### Practice 7.5
**Question:** What is the mass of 0.150 mol of \( \text{Na}_2\text{SO}_4 \)?

---

#### Practice 7.6
**Question:** How many moles and molecules are there in 500.0 g of \( \text{HC}_2\text{H}_3\text{O}_2 \)?

---

### Explanation and Steps:

**For Practice 7.5:**
1. **Determine Molar Mass of \( \text{Na}_2\text{SO}_4 \):**
   - Sodium (Na): \( 22.99 \, \text{g/mol} \)
   - Sulfur (S): \( 32.07 \, \text{g/mol} \)
   - Oxygen (O): \( 16.00 \, \text{g/mol} \)

   Therefore, the molar mass of \( \text{Na}_2\text{SO}_4 \) is calculated as:
   \[
   (2 \times 22.99) + 32.07 + (4 \times 16.00) = 45.98 + 32.07 + 64.00 = 142.05 \, \text{g/mol}
   \]

2. **Calculate the Mass:**
   \[
   \text{Mass} = \text{Moles} \times \text{Molar Mass} = 0.150 \, \text{mol} \times 142.05 \, \text{g/mol} = 21.31 \, \text{g}
   \]

**For Practice 7.6:**
1. **Determine Molar Mass of \( \text{HC}_2\text{H}_3\text{O}_2 \):**
   - Hydrogen (H): \( 1.01 \, \text{g/mol} \)
   - Carbon (C): \( 12.01 \, \text{g/mol} \)
   - Oxygen (O): \( 16.00 \, \text{g/mol} \)

   Therefore, the molar mass of \( \text{HC}_2\text{H}_3\text{O}_2 \) is calculated as:
   \[
   1.01 + (2 \
Transcribed Image Text:### Practice Questions for Chemistry Students #### Practice 7.5 **Question:** What is the mass of 0.150 mol of \( \text{Na}_2\text{SO}_4 \)? --- #### Practice 7.6 **Question:** How many moles and molecules are there in 500.0 g of \( \text{HC}_2\text{H}_3\text{O}_2 \)? --- ### Explanation and Steps: **For Practice 7.5:** 1. **Determine Molar Mass of \( \text{Na}_2\text{SO}_4 \):** - Sodium (Na): \( 22.99 \, \text{g/mol} \) - Sulfur (S): \( 32.07 \, \text{g/mol} \) - Oxygen (O): \( 16.00 \, \text{g/mol} \) Therefore, the molar mass of \( \text{Na}_2\text{SO}_4 \) is calculated as: \[ (2 \times 22.99) + 32.07 + (4 \times 16.00) = 45.98 + 32.07 + 64.00 = 142.05 \, \text{g/mol} \] 2. **Calculate the Mass:** \[ \text{Mass} = \text{Moles} \times \text{Molar Mass} = 0.150 \, \text{mol} \times 142.05 \, \text{g/mol} = 21.31 \, \text{g} \] **For Practice 7.6:** 1. **Determine Molar Mass of \( \text{HC}_2\text{H}_3\text{O}_2 \):** - Hydrogen (H): \( 1.01 \, \text{g/mol} \) - Carbon (C): \( 12.01 \, \text{g/mol} \) - Oxygen (O): \( 16.00 \, \text{g/mol} \) Therefore, the molar mass of \( \text{HC}_2\text{H}_3\text{O}_2 \) is calculated as: \[ 1.01 + (2 \
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