Homework Help is Here – Start Your Trial Now!
Science
Chemistry
2. How many grams are in 4.22 moles of Al2(SO4)3? (

2. How many grams are in 4.22 moles of Al2(SO4)3? (

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
**Question:** 2. How many grams are in 4.22 moles of Al₂(SO₄)₃? **Explanation:** This question requires the calculation of mass from moles for the compound aluminum sulfate, Al₂(SO₄)₃. In order to find the answer, you would need to use the molar mass of Al₂(SO₄)₃. By multiplying the number of moles by the molar mass (grams per mole), you can determine the total mass in grams. **Steps for Solution:** 1. **Find the molar mass of Al₂(SO₄)₃**: - Aluminum (Al): 26.98 g/mol - Sulfur (S): 32.07 g/mol - Oxygen (O): 16.00 g/mol Molar mass of Al₂(SO₄)₃ = [2(26.98) + 3(32.07 + 4(16.00))] g/mol 2. **Calculate the mass**: - Mass (g) = Moles × Molar mass Substitute the values to find the final mass in grams.
Transcribed Image Text:**Question:** 2. How many grams are in 4.22 moles of Al₂(SO₄)₃? **Explanation:** This question requires the calculation of mass from moles for the compound aluminum sulfate, Al₂(SO₄)₃. In order to find the answer, you would need to use the molar mass of Al₂(SO₄)₃. By multiplying the number of moles by the molar mass (grams per mole), you can determine the total mass in grams. **Steps for Solution:** 1. **Find the molar mass of Al₂(SO₄)₃**: - Aluminum (Al): 26.98 g/mol - Sulfur (S): 32.07 g/mol - Oxygen (O): 16.00 g/mol Molar mass of Al₂(SO₄)₃ = [2(26.98) + 3(32.07 + 4(16.00))] g/mol 2. **Calculate the mass**: - Mass (g) = Moles × Molar mass Substitute the values to find the final mass in grams.
Expert Solution
Molecular mass

The molecular mass of anhydrous Alminium sulphate Al2(SO4)3 is 342.15 g/mol .

Therefore number of grams in  one mole of Al2(SO4)3 is 342.15 g/mol 

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Mole Concept
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS