p q r ∼q∼q p∨∼qp∨∼q ∼p∼p r∧∼pr∧∼p (p∨∼q)→(r∧∼p)(p∨∼q)→(r∧∼p) T T T T T F T F T T F F F T T F T F F F T F F F
p q r ∼q∼q p∨∼qp∨∼q ∼p∼p r∧∼pr∧∼p (p∨∼q)→(r∧∼p)(p∨∼q)→(r∧∼p) T T T T T F T F T T F F F T T F T F F F T F F F
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Complete the truth table for the following compound statement.(p∨∼q)→(r∧∼p)(p∨∼q)→(r∧∼p)
p | q | r | ∼q∼q | p∨∼qp∨∼q | ∼p∼p | r∧∼pr∧∼p | (p∨∼q)→(r∧∼p)(p∨∼q)→(r∧∼p) |
---|---|---|---|---|---|---|---|
T | T | T | |||||
T | T | F | |||||
T | F | T | |||||
T | F | F | |||||
F | T | T | |||||
F | T | F | |||||
F | F | T | |||||
F | F | F |
Is the compound statement a tautology?
- No, the statement is not a tautology.
- Yes, the statement is a tautology.
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