pplying Kirchhoff's Laws to the electrical network in the figure, the currents I,, ,, and I, are the solution of the system - 12 + I3 = 0 311 + 512 512 + 413 = 28 %3D = 26 %3D where a = 3, b = 5, c = 4, v, = 26, and v, = 28. Find the currents. %3D %3D 1 %3D 2 3 = , volts V2volts
pplying Kirchhoff's Laws to the electrical network in the figure, the currents I,, ,, and I, are the solution of the system - 12 + I3 = 0 311 + 512 512 + 413 = 28 %3D = 26 %3D where a = 3, b = 5, c = 4, v, = 26, and v, = 28. Find the currents. %3D %3D 1 %3D 2 3 = , volts V2volts
Introductory Circuit Analysis (13th Edition)
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Publisher:Robert L. Boylestad
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Applying Kirchhoff's Laws to the electrical network in the figure, the currents and I1,I2 and I3 are the solution of the system
![Applying Kirchhoff's Laws to the electrical network in the figure, the currents I,, I,, and I, are the solution of the system
I2 + I3 = 0
31 +512
512 + 413
= 26
= 28
where a = 3, b = 5, c = 4, v, = 26, and v2
= 28. Find the currents.
I, =
I, =
Iz =
I3
a Q
, volts
V2 volts
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Transcribed Image Text:Applying Kirchhoff's Laws to the electrical network in the figure, the currents I,, I,, and I, are the solution of the system
I2 + I3 = 0
31 +512
512 + 413
= 26
= 28
where a = 3, b = 5, c = 4, v, = 26, and v2
= 28. Find the currents.
I, =
I, =
Iz =
I3
a Q
, volts
V2 volts
Need Help?
Read It
Watch It
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