Pp 35 k PL 80 k 18 ft 8 ft A simply supported beam (AB) of 18 ft with an overhang (BC) of another 8 ft is loaded at the free end C with a concentrated service dead load of 35 k and a service live load of 80 k. The beam is laterally supported at both supports (at A and B) and there is no bracing at the free end (at C) of the cantilever. Neglect the weight of the beam, select the lightest W section of A 992 steel for this beam (ABC) that can safely carry the applied loads the N

Pp 35 k PL 80 k 18 ft 8 ft A simply supported beam (AB) of 18 ft with an overhang (BC) of another 8 ft is loaded at the free end C with a concentrated service dead load of 35 k and a service live load of 80 k. The beam is laterally supported at both supports (at A and B) and there is no bracing at the free end (at C) of the cantilever. Neglect the weight of the beam, select the lightest W section of A 992 steel for this beam (ABC) that can safely carry the applied loads the N

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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note: SN is equal to 18, topload will now be 118kN
1. According to the requirements of the AISC-Specifications for doubly symmetric members and singly symmetric members, the interaction of flexure and compression shall be limited by Equations: a) H1 -1a and H1 -1b. b) El-la and E1 -1b. c) G1 -la and G1 -1b. d) F1-la and F1 -1b. e) C1 -la and C1 -lb. 2. The beams framing into columns are commonly supported with framing angles or brackets on the sides of the columns. These eccentrically applied loads produce: a) Axial Tension. b) Shear forces. /c) Bending moments. d) Axial compression. e) Torques. 3. The required total flexural strength of a beam-column member must at least equal the sum of the: a) first-order moments only. b) Second-order moments only. c) first-order and second-order axial loads. d) first-order and second-order moments. e) Non the above. 4. The first-order moment using LRFD load combinations, due to the lateral translation of the structure only, is referred to as: a) Mnt b) Mit c) Mr d) Pnt e) Pit
6-1.2-1: Find lightest W14 for L = 20', P = 600k E = 29,000ksi, Fb = 30ksi and Fv = 20ksi. 30. CONTINUOUS BEAM - TWO EQUAL SPANS-CONCENTRATED LOAD AT CENTER OF ONE SPAN Total Equiv. Uniform Load 13 p 8 P 2 R,= V₁.. 32 R R₂ R₁ R₂= V₁ + V₂. 11 p 16 V₁ R= V₁ V₂ Mmax (at point of load). M. (at support R)..... .......... Amax (at 0.480 / from R.).... M Imax Shear Moment M₁ V₂ ********* ***************** 11 = 11 P 32 - 19 p 32 13 64 = 3. Pl PI 32 0.015 P³ El
6- In simply supported beams, the shear stresses increase when approach to the mid span. O True O False
A 7-m simply supported rectangular beam has dimensions of 300mm x 600 mm and an effective depth of 530 mm. It is subjected to uniform dead load of 20 kN/m and uniform live load of 30 kN/m. Use f'c = 28 MPa and fyt = 276 MPa for 10 mm diameter U-stirrup. Design the required spacing of the shear reinforcement at critical section. Also, design the required spacing under Torsion load of 2 KN-m.
ASAP PLS THANKS!
10-19. Design a beam for a 24-ft simple span to support the working uniform loads of 3.0 k/ft. The maximum per- WD = 1.25 k/ft (includes beam self-weight) and w missible total load deflection under working loads is 1/360 of the span. Use 50 ksi steel and consider moment, shear, and deflection. The beam is to be braced laterally at its ends and midspan only. Determine C. (Ans. W24 x 62 LRFD and ASD) Solant th linkennt 61.000 10.30 ilable WIZ
Verify the bending resistance and global stability of the beam. Gravity load is 0.9kN/m, concentrated load 100 kN is applied in the midpoint of the span. Q235 steel is used. a. No brace in the middle of the span. Concentrated load is applied on the top flange. b. No brace in the middle of the span. Concentrated load is applied on the bottom flange. (optional) C. Braced in the middle of the span. Concentrated load is applied on the top flange. d. Same as (a), use Q345B steel. 0.9kN/m 200×12 5000 100KN 5000 I 776x8 200×12
Prob #l: Design uniform kive load of 22,500 Nm. exclusive of its own weight . Assume the beam to have a simple span of 6m. Use ACI Specs, with fe-20 MPa, f = 138 MPa., 'n=9, Va =0,09| fe and a rectangvlar beam reinforced for tension enly to carry a Va= 22,500 Nm figire : Prob #2: A beam having an 8m. simple span has a cross-section shown in the figure. Defermiìne the maximum concentrated load that this beam can carry besides its own weight. Use fe=7MP., f=124 ME. and n= 10. Figyre: 100 200 100 400mm 100 N.A. --N.A. 600mm 400 5Somm 200mm 550-X 150 n As OSt 4-25mmd Tensicn Bar 400mm
The frame shown below is subjected to uniformly distributed load of 2.6KP.. Determine the maximum moment of member BF (assume simple beam support) A E, 1.5m F 1.5m 351 C 1.5m H 3m B
3. Design the cantilever beam for bending (tension zone), ultimate uniform distributed load on the beam 40kN/m. Use fe-24MPa, fy-420MPa and 020mm(A6-314mm²), cover40mm, stirrups 10mm. Did the cantilever beam need reinforcement at compression zone, why? 40 -3.0m- h=50cm b-30cm 500mm 300mm
Design a W section for a beam of A36 steel Fy=248 Mpa to carry a uniform load of 293 kN/m on a simply supported span of 1.5 m. Assume lateral bracing is adequate for stability Pa. has Properties of W sections available W 12 x 27 W 12x 31 W 14 x 26 Wt of beam 394.9 N/m 453.4 N/m 380.27 N/m Area 5129 5890 4948 Depth (d) Flange width (b) Flange thickness (t) Web thickness (tw) Moment of inertia (1,) Section Modulus (S,) 303.78 165.02 307.09 165-74 352.81 127.64 10.16 11.81 10.62 6.02 673 648 84.9 x 10° mm 560.4 x 10 mm 99.5 x 10 mm 101.56 x 10° mm nmer 674.3x 10 mm 575.2 x 10 mm ht to bnan