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6-1.2-1: Find lightest W14 for L = 20', P = 600k E = 29,000ksi, Fb = 30ksi and Fv = 20ksi. 30. CONTINUOUS BEAM-TWO EQUAL SPANS-CONCENTRATED LOAD AT CENTER OF ONE SPAN Total Equiv. Uniform Load 13 p 8 P 2 R,= V₁.. 32 R R₂ R₁ R₂= V₁ + V₂. 11 p 16 V₁ R= V₁. V₂ Mmax (at point of load). M. (at support R)..... .......... Amax (at 0.480 / from R.).... M Inax Shear Moment M₁ V₂ ********** ********** 11 = 11 P 11 32 19 p 32 = 3. Pl 13 64 = PI 32 0.015 P³ El

6-1.2-1: Find lightest W14 for L = 20', P = 600k E = 29,000ksi, Fb = 30ksi and Fv = 20ksi. 30. CONTINUOUS BEAM-TWO EQUAL SPANS-CONCENTRATED LOAD AT CENTER OF ONE SPAN Total Equiv. Uniform Load 13 p 8 P 2 R,= V₁.. 32 R R₂ R₁ R₂= V₁ + V₂. 11 p 16 V₁ R= V₁. V₂ Mmax (at point of load). M. (at support R)..... .......... Amax (at 0.480 / from R.).... M Inax Shear Moment M₁ V₂ ********** ********** 11 = 11 P 11 32 19 p 32 = 3. Pl 13 64 = PI 32 0.015 P³ El

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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6-1.2-1: Find lightest W14 for L = 20', P = 600k E = 29,000ksi, Fb = 30ksi and Fv = 20ksi. 30. CONTINUOUS BEAM - TWO EQUAL SPANS-CONCENTRATED LOAD AT CENTER OF ONE SPAN Total Equiv. Uniform Load 13 p 8 P 2 R,= V₁.. 32 R R₂ R₁ R₂= V₁ + V₂. 11 p 16 V₁ R= V₁ V₂ Mmax (at point of load). M. (at support R)..... .......... Amax (at 0.480 / from R.).... M Imax Shear Moment M₁ V₂ ********* ***************** 11 = 11 P 32 - 19 p 32 13 64 = 3. Pl PI 32 0.015 P³ El
Transcribed Image Text:6-1.2-1: Find lightest W14 for L = 20', P = 600k E = 29,000ksi, Fb = 30ksi and Fv = 20ksi. 30. CONTINUOUS BEAM - TWO EQUAL SPANS-CONCENTRATED LOAD AT CENTER OF ONE SPAN Total Equiv. Uniform Load 13 p 8 P 2 R,= V₁.. 32 R R₂ R₁ R₂= V₁ + V₂. 11 p 16 V₁ R= V₁ V₂ Mmax (at point of load). M. (at support R)..... .......... Amax (at 0.480 / from R.).... M Imax Shear Moment M₁ V₂ ********* ***************** 11 = 11 P 32 - 19 p 32 13 64 = 3. Pl PI 32 0.015 P³ El
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