Pourbaix diagram for aluminum (Al) at 25°C is given in Figure Q2. Assume [Al**] = 10* M, and [AlO;] = 10 M. (i) Give the chemical reaction for the vertical line (B) in Figure Q2. (ii) Determine the equilibrium constant K for this chemical reaction. 0.6 04 02 0.0- ALO, AlO, -0.2 (B) -0.4 0.6- -0.8 1.0- -1.2- -14 1.6 Corrosion Passivation Corrosion 2.0- -22 Al Immunity -2 -1 0I2 3 56789 10 11 12 13 14 pll Figure Q2 Eº, V 0.0000 Standard hydrogen electrode Reaction 2H+ + 2e +→ H2 Pb2+ + 2e Pb -0.126 Sn2+ + 2e" + Sn -0.138 Mo3+ + 3e" Mo -0.200 Ni2+ + 2e" > Ni -0.257 Co2+ + 2e + Co Cd2+ + 2e Cd Fe2+ + 2e + Fe -0.28 -0.403 -0.447 Cr3+ + 3e + Cr -0.744 Zn2+ + 2e" +→ Zn -0.762 Nh3+ + 3e" → Nb -1.099 (also called Columbium, Cb) Mn2+ + 2e ( Mn -1.185 Zr+ + 4e" → Zr -1.45 Ti2+ + 2e → Ti -1.630 Al3+ + 3e + Al -1.662 Potential (V) ---- i ei eir
Pourbaix diagram for aluminum (Al) at 25°C is given in Figure Q2. Assume [Al**] = 10* M, and [AlO;] = 10 M. (i) Give the chemical reaction for the vertical line (B) in Figure Q2. (ii) Determine the equilibrium constant K for this chemical reaction. 0.6 04 02 0.0- ALO, AlO, -0.2 (B) -0.4 0.6- -0.8 1.0- -1.2- -14 1.6 Corrosion Passivation Corrosion 2.0- -22 Al Immunity -2 -1 0I2 3 56789 10 11 12 13 14 pll Figure Q2 Eº, V 0.0000 Standard hydrogen electrode Reaction 2H+ + 2e +→ H2 Pb2+ + 2e Pb -0.126 Sn2+ + 2e" + Sn -0.138 Mo3+ + 3e" Mo -0.200 Ni2+ + 2e" > Ni -0.257 Co2+ + 2e + Co Cd2+ + 2e Cd Fe2+ + 2e + Fe -0.28 -0.403 -0.447 Cr3+ + 3e + Cr -0.744 Zn2+ + 2e" +→ Zn -0.762 Nh3+ + 3e" → Nb -1.099 (also called Columbium, Cb) Mn2+ + 2e ( Mn -1.185 Zr+ + 4e" → Zr -1.45 Ti2+ + 2e → Ti -1.630 Al3+ + 3e + Al -1.662 Potential (V) ---- i ei eir
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![Pourbaix diagram for aluminum (Al) at 25°C is given in Figure Q2. Assume [Al³*] = 10* M,
and [AlO,] = 10 M.
(i) Give the chemical reaction for the vertical line (B) in Figure Q2.
(ii) Determine the equilibrium constant K for this chemical reaction.
04
0.2
ALO,
AlO,
0.0-
-0.2
(B)
las
-0.4
-0.6-
-0.8-
-1.0-
-1.24
-14
Corrosion
Passivation
Corresion
Al
-2.4.
Immunity
-2 -1 0I 23 45 6 78 9 10 11 12 13 14
pll
Figure Q2
Reaction
Eº, V
2H+ + 2e H2
Pb2+ + 2e + Pb
0.0000 Standard hydrogen electrode
-0.126
Sn2+ + 2e" → Sn
-0.138
Mo3+ + 3e" +→ Mo
-0.200
Ni2+ + 2e > Ni
-0.257
Co2+ + 2e → Co
-0.28
Cd2+ + 2e Cd
Fe2+ + 2e + Fe
Cr3+ + 3e + Cr
-0.403
-0.447
-0.744
Zn2+ + 2e Zn
-0.762
Nh3+ + 3e Nb
-1.099
(also called Columbium, Cb)
Mn2+ + 2e" Mn
-1.185
Zr4+ + 4e" Zr
-1.45
Ti2+ + 2e + Ti
-1.630
Al3+ + 3e +→ Al
-1.662
Potential (V)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0e392014-20be-4f77-91aa-6d5fd4b480d3%2F079e3225-caf9-4c0f-8c77-aabde1506d65%2Fc6bd9ti_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Pourbaix diagram for aluminum (Al) at 25°C is given in Figure Q2. Assume [Al³*] = 10* M,
and [AlO,] = 10 M.
(i) Give the chemical reaction for the vertical line (B) in Figure Q2.
(ii) Determine the equilibrium constant K for this chemical reaction.
04
0.2
ALO,
AlO,
0.0-
-0.2
(B)
las
-0.4
-0.6-
-0.8-
-1.0-
-1.24
-14
Corrosion
Passivation
Corresion
Al
-2.4.
Immunity
-2 -1 0I 23 45 6 78 9 10 11 12 13 14
pll
Figure Q2
Reaction
Eº, V
2H+ + 2e H2
Pb2+ + 2e + Pb
0.0000 Standard hydrogen electrode
-0.126
Sn2+ + 2e" → Sn
-0.138
Mo3+ + 3e" +→ Mo
-0.200
Ni2+ + 2e > Ni
-0.257
Co2+ + 2e → Co
-0.28
Cd2+ + 2e Cd
Fe2+ + 2e + Fe
Cr3+ + 3e + Cr
-0.403
-0.447
-0.744
Zn2+ + 2e Zn
-0.762
Nh3+ + 3e Nb
-1.099
(also called Columbium, Cb)
Mn2+ + 2e" Mn
-1.185
Zr4+ + 4e" Zr
-1.45
Ti2+ + 2e + Ti
-1.630
Al3+ + 3e +→ Al
-1.662
Potential (V)
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