Potentially Useful Reference Information Kw = 0.114 x 10-14 at 0°C Kw = 0.465 x 10-14 at 15°C Kw = 0.681 x 10´14 at 20°C Kw = 1.00 x 10 14 at 25°C Kw = 2.42 x 10-14 at 37°C Kw = 9.61 x 10-14 at 60°C Acid Ka HCI 1.3 x 106 H2SO4 1 x 103 HNO3 2.4 x 101 HSO4 1.2 x 10-2 H3PO4 7.5 x 10-3 A student measures the temperature of an NaOH solution to be 15 degrees C. The student then measures the pH of this NaOH solution to be pH = 12.39. H3CCOOH 1.8 x 10-5 H2CO3 4.3 x 10-7 H2PO4 6.2 x 10-8 Determine the molarity of this sodium hydroxide solution at 15°C. Error analysis is not necessary, but report your answer with 2 HCO3 4.8 x 10-11 significant figures. HPO,2- 4.8 x 1013

Chemistry for Engineering Students
3rd Edition
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter5: Gases
Section: Chapter Questions
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**Potentially Useful Reference Information**
- \( K_w = 0.114 \times 10^{-14} \) at 0°C
- \( K_w = 0.465 \times 10^{-14} \) at 15°C
- \( K_w = 0.681 \times 10^{-14} \) at 20°C
- \( K_w = 1.00 \times 10^{-14} \) at 25°C
- \( K_w = 2.42 \times 10^{-14} \) at 37°C
- \( K_w = 9.61 \times 10^{-14} \) at 60°C

**Acid Dissociation Constants (Ka)**
| Acid      | \( K_a \)          |
|-----------|--------------------|
| HCl       | \( 1.3 \times 10^6 \)  |
| \( H_2SO_4 \)  | \( 1 \times 10^3 \)    |
| HNO3      | \( 2.4 \times 10^1 \)   |
| \( HSO_4^- \)  | \( 1.2 \times 10^{-2} \) |
| \( H_3PO_4 \)  | \( 7.5 \times 10^{-3} \) |
| \( H_3CCOOH \) | \( 1.8 \times 10^{-5} \) |
| \( H_2CO_3 \)  | \( 4.3 \times 10^{-7} \) |
| \( H_2PO_4^- \) | \( 6.2 \times 10^{-8} \) |
| \( HCO_3^- \)  | \( 4.8 \times 10^{-11} \) |
| \( HPO_4^{2-} \) | \( 4.8 \times 10^{-13} \) |

**Problem Statement:**
A student measures the temperature of an NaOH solution to be 15 degrees C. The student then measures the pH of this NaOH solution to be pH = 12.39.

Determine the molarity of this sodium hydroxide solution at 15°C. Error analysis is not necessary, but report your answer with 2 significant figures.
Transcribed Image Text:**Potentially Useful Reference Information** - \( K_w = 0.114 \times 10^{-14} \) at 0°C - \( K_w = 0.465 \times 10^{-14} \) at 15°C - \( K_w = 0.681 \times 10^{-14} \) at 20°C - \( K_w = 1.00 \times 10^{-14} \) at 25°C - \( K_w = 2.42 \times 10^{-14} \) at 37°C - \( K_w = 9.61 \times 10^{-14} \) at 60°C **Acid Dissociation Constants (Ka)** | Acid | \( K_a \) | |-----------|--------------------| | HCl | \( 1.3 \times 10^6 \) | | \( H_2SO_4 \) | \( 1 \times 10^3 \) | | HNO3 | \( 2.4 \times 10^1 \) | | \( HSO_4^- \) | \( 1.2 \times 10^{-2} \) | | \( H_3PO_4 \) | \( 7.5 \times 10^{-3} \) | | \( H_3CCOOH \) | \( 1.8 \times 10^{-5} \) | | \( H_2CO_3 \) | \( 4.3 \times 10^{-7} \) | | \( H_2PO_4^- \) | \( 6.2 \times 10^{-8} \) | | \( HCO_3^- \) | \( 4.8 \times 10^{-11} \) | | \( HPO_4^{2-} \) | \( 4.8 \times 10^{-13} \) | **Problem Statement:** A student measures the temperature of an NaOH solution to be 15 degrees C. The student then measures the pH of this NaOH solution to be pH = 12.39. Determine the molarity of this sodium hydroxide solution at 15°C. Error analysis is not necessary, but report your answer with 2 significant figures.
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