(POTENTIAL ENERGY CURVES) A 10 kg particle moves under the potential shown below, where U(x) has units of Joules and a is measured in meters. The potential energy is 20 J for all x 210 m. (a) What is the force on the particle when it is at x = 3 m? (b) What minimum speed (moving to the left) must the particle have at x = 11 m in order to reach x = 2 m? = (c) Describe the motion of the particle if it begins at x = 1 m with a velocity of UT +√12 m/s. A complete answer would discuss turning points and limitations to the range of motion, if any, as well as regions where the particle speed increases, decreases, and remains constant.

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**Potential Energy Curves**

A 10 kg particle moves under the potential shown below, where \( U(x) \) has units of Joules and \( x \) is measured in meters. The potential energy is 20 J for all \( x \geq 10 \) m.

**(a)** What is the force on the particle when it is at \( x = 3 \) m?

**(b)** What minimum speed (moving to the left) must the particle have at \( x = 11 \) m in order to reach \( x = 2 \) m?

**(c)** Describe the motion of the particle if it begins at \( x = 1 \) m with a velocity of \( v_x = +\sqrt{12} \) m/s. A complete answer would discuss turning points and limitations to the range of motion, if any, as well as regions where the particle speed increases, decreases, and remains constant.

**(d)** If the particle instead begins at \( x = 1 \) m with a velocity \( v_x > \sqrt{12} \) m/s, does the particle ever turn around? Explain.

**Graph Explanation:**

- The graph displays potential energy \( U(x) \) in Joules on the y-axis and position \( x \) in meters on the x-axis.
- For \( x \leq 0 \), \( U(x) \) is at 80 J.
- From \( x = 0 \) to \( x = 2 \), \( U(x) \) decreases linearly down to -20 J.
- From \( x = 2 \) to \( x = 4 \), \( U(x) \) rises sharply to 20 J.
- From \( x = 4 \) to \( x = 8 \), \( U(x) \) remains constant at 20 J.
- From \( x = 8 \) to \( x = 10 \), \( U(x) \) decreases linearly to reach 20 J again.
- For \( x \geq 10 \), \( U(x) \) remains constant at 20 J.
Transcribed Image Text:**Potential Energy Curves** A 10 kg particle moves under the potential shown below, where \( U(x) \) has units of Joules and \( x \) is measured in meters. The potential energy is 20 J for all \( x \geq 10 \) m. **(a)** What is the force on the particle when it is at \( x = 3 \) m? **(b)** What minimum speed (moving to the left) must the particle have at \( x = 11 \) m in order to reach \( x = 2 \) m? **(c)** Describe the motion of the particle if it begins at \( x = 1 \) m with a velocity of \( v_x = +\sqrt{12} \) m/s. A complete answer would discuss turning points and limitations to the range of motion, if any, as well as regions where the particle speed increases, decreases, and remains constant. **(d)** If the particle instead begins at \( x = 1 \) m with a velocity \( v_x > \sqrt{12} \) m/s, does the particle ever turn around? Explain. **Graph Explanation:** - The graph displays potential energy \( U(x) \) in Joules on the y-axis and position \( x \) in meters on the x-axis. - For \( x \leq 0 \), \( U(x) \) is at 80 J. - From \( x = 0 \) to \( x = 2 \), \( U(x) \) decreases linearly down to -20 J. - From \( x = 2 \) to \( x = 4 \), \( U(x) \) rises sharply to 20 J. - From \( x = 4 \) to \( x = 8 \), \( U(x) \) remains constant at 20 J. - From \( x = 8 \) to \( x = 10 \), \( U(x) \) decreases linearly to reach 20 J again. - For \( x \geq 10 \), \( U(x) \) remains constant at 20 J.
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