Points A and B are separated by a lake. To find the distance between them, a surveyor locates a point C on land such than ZCAB = 51.2°. Find the distance across the lake from A to B. B 511 yd NOTE: The triangle is NOT drawn to scale. distance = yd 325 yd 51.2° 9 Enter your answer as a number: your answer should be accurate to 2 decimal places.

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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Problem Description

Points A and B are separated by a lake. To find the distance between them, a surveyor locates a point C on land such that \(\angle CAB = 51.2^\circ\). Find the distance across the lake from A to B.

### Illustration

The diagram shows a triangle with vertices labeled A, B, and C. 

- Line segment \(CA\) measures 325 yards.
- Line segment \(CB\) measures 511 yards.
- \(\angle CAB\) is marked as 51.2 degrees.

The path across the lake forms the missing side of the triangle from point A to B.

### Note

- The triangle is NOT drawn to scale.

### Calculation

To find the distance across the lake from A to B, enter your answer as a number, and ensure it is accurate to two decimal places.

\[ \text{distance} = \_\_\_\_ \text{ yd} \]

### Instructions

- Apply the law of cosines to calculate the distance \(AB\):   

\[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) \]

- Where:
  - \(a = 325\) yd (CA)
  - \(b = 511\) yd (CB)
  - \(C = 51.2^\circ\) (angle CAB)

\[ \text{distance} = \text{calculated value} \] (rounded to two decimal places) 

Enter your answer in the provided space.
Transcribed Image Text:### Problem Description Points A and B are separated by a lake. To find the distance between them, a surveyor locates a point C on land such that \(\angle CAB = 51.2^\circ\). Find the distance across the lake from A to B. ### Illustration The diagram shows a triangle with vertices labeled A, B, and C. - Line segment \(CA\) measures 325 yards. - Line segment \(CB\) measures 511 yards. - \(\angle CAB\) is marked as 51.2 degrees. The path across the lake forms the missing side of the triangle from point A to B. ### Note - The triangle is NOT drawn to scale. ### Calculation To find the distance across the lake from A to B, enter your answer as a number, and ensure it is accurate to two decimal places. \[ \text{distance} = \_\_\_\_ \text{ yd} \] ### Instructions - Apply the law of cosines to calculate the distance \(AB\): \[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) \] - Where: - \(a = 325\) yd (CA) - \(b = 511\) yd (CB) - \(C = 51.2^\circ\) (angle CAB) \[ \text{distance} = \text{calculated value} \] (rounded to two decimal places) Enter your answer in the provided space.
Expert Solution
Step 1

For any triangle: ABC, using the cosine rule, it can be written that: BC=AC2+AB2-2AC×AB×cosA.

The roots of the quadratic equation: ax2+bx+c=0 is calculated using the quadratic formula: x1,2=-b±b2-4ac2a.

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