Create the program being demonstrated in the picture below Pointers and Arrays• Example:char letters(26];char *pc1 letters; /* Equivalent pointer values. */char *pc2 &letters;char *pc3 = &letters [0];%3Dletters[4] = 'e'; /* Equivalent indexes. /pc1[4] = 'e';*(letters + 4) = 'e';%3D*(pc2 + 4) = 'e';pc3 = &letters[10]; /* Equivalent addresses. /pc3 - &pc1[10];pc3 = letters + 10;pc3 = pc2 + 10;%3D%3DDOLL

I give the same code in text format and also provide its output and code screenshot.

Pointers and Arrays Example: char letters (26]; char *pc1 letters; /* Equivalent pointer values. char *pc2 = &letters; char *pc3 = &letters[0]; letters[4] pc1[4] = 'e'; *(letters + 4) = 'e'; * (pc2 + 4) = 'e'; = 'e'; /* Equivalent indexes. / %3D %3D %3D %3D pc3 = &letters[10]; /* Equivalent addresses. / pc3 &pc1[10]; pc3 = letters + 10; pc3 = pc2 + 10; %3D %3D

Pointers and Arrays Example: char letters (26]; char pc1 letters; / Equivalent pointer values. char pc2 = &letters; char pc3 = &letters[0]; letters[4] pc1[4] = 'e'; (letters + 4) = 'e'; (pc2 + 4) = 'e'; = 'e'; /* Equivalent indexes. / %3D %3D %3D %3D pc3 = &letters[10]; /* Equivalent addresses. / pc3 &pc1[10]; pc3 = letters + 10; pc3 = pc2 + 10; %3D %3D

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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