pOH = 10.65 [OH]- %3D M [H+] = M SHOW HINT pOH = 4.28 [OH] - M [H+]- M SHOW HINT pOH - 3.76 (OH"]- [H*]-

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The image shows a series of exercises related to the calculation of hydroxide ion concentration \([OH^-]\) and hydrogen ion concentration \([H^+]\) from given pOH values. This is useful for understanding acid-base chemistry.

1. **Exercise 1**
   - Given: pOH = 10.65
   - Tasks:
     - Calculate \([OH^-]\) in molarity (M).
     - Calculate \([H^+]\) in molarity (M).
   - A "Show Hint" option is available to assist with calculations.

2. **Exercise 2**
   - Given: pOH = 4.28
   - Tasks:
     - Calculate \([OH^-]\) in molarity (M).
     - Calculate \([H^+]\) in molarity (M).
   - A "Show Hint" option is available to assist with calculations.

3. **Exercise 3**
   - Given: pOH = 3.76
   - Tasks:
     - Calculate \([OH^-]\) in molarity (M).
     - Calculate \([H^+]\) in molarity (M).
   - A "Show Hint" option is available to assist with calculations.

These exercises require knowledge of the relationships between pOH, pH, and the concentrations of \([OH^-]\) and \([H^+]\), using the formulas:
- pH + pOH = 14
- \([OH^-] = 10^{-\text{pOH}}\)
- \([H^+] = 10^{-\text{pH}}\)
Transcribed Image Text:The image shows a series of exercises related to the calculation of hydroxide ion concentration \([OH^-]\) and hydrogen ion concentration \([H^+]\) from given pOH values. This is useful for understanding acid-base chemistry. 1. **Exercise 1** - Given: pOH = 10.65 - Tasks: - Calculate \([OH^-]\) in molarity (M). - Calculate \([H^+]\) in molarity (M). - A "Show Hint" option is available to assist with calculations. 2. **Exercise 2** - Given: pOH = 4.28 - Tasks: - Calculate \([OH^-]\) in molarity (M). - Calculate \([H^+]\) in molarity (M). - A "Show Hint" option is available to assist with calculations. 3. **Exercise 3** - Given: pOH = 3.76 - Tasks: - Calculate \([OH^-]\) in molarity (M). - Calculate \([H^+]\) in molarity (M). - A "Show Hint" option is available to assist with calculations. These exercises require knowledge of the relationships between pOH, pH, and the concentrations of \([OH^-]\) and \([H^+]\), using the formulas: - pH + pOH = 14 - \([OH^-] = 10^{-\text{pOH}}\) - \([H^+] = 10^{-\text{pH}}\)
**Question 3**

Calculate the molar concentrations of \( \text{H}^+ \) and \( \text{OH}^- \) in solutions that have the following pOH values. Enter values in scientific notation, for example, 0.0010 would be \( 1.0 \times 10^{-3} \).

- **pOH = 12.27**

  \([ \text{OH}^- ] =\) \_\_\_\_\_\_\_\_\_ M

  \([ \text{H}^+ ] =\) \_\_\_\_\_\_\_\_\_ M

- **pOH = 6.14**

  \([ \text{OH}^- ] =\) \_\_\_\_\_\_\_\_\_ M

  \([ \text{H}^+ ] =\) \_\_\_\_\_\_\_\_\_ M

**SHOW HINT**
Transcribed Image Text:**Question 3** Calculate the molar concentrations of \( \text{H}^+ \) and \( \text{OH}^- \) in solutions that have the following pOH values. Enter values in scientific notation, for example, 0.0010 would be \( 1.0 \times 10^{-3} \). - **pOH = 12.27** \([ \text{OH}^- ] =\) \_\_\_\_\_\_\_\_\_ M \([ \text{H}^+ ] =\) \_\_\_\_\_\_\_\_\_ M - **pOH = 6.14** \([ \text{OH}^- ] =\) \_\_\_\_\_\_\_\_\_ M \([ \text{H}^+ ] =\) \_\_\_\_\_\_\_\_\_ M **SHOW HINT**
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