**Chemical Decomposition of Isopropyl Alcohol****Introduction**Isopropyl alcohol is the main ingredient in rubbing alcohol. It can decompose into acetone (the main ingredient in nail polish remover) and hydrogen gas according to the following reaction:\[ \text{C}_3\text{H}_7\text{OH}(g) \rightarrow \text{C}_2\text{H}_6\text{CO}(g) + \text{H}_2(g) \]**Problem Statement**At 180°C, the equilibrium constant for the decomposition is 0.45. If 43 mL (density = 0.785 g/mL) of isopropyl alcohol is placed in a 2.0 L vessel and heated to 180°C, what percentage remains undissociated at equilibrium?**Solution Approach**To solve this problem, you'll need to follow these steps: 1. **Determine the initial moles of isopropyl alcohol:** - Calculate the mass of isopropyl alcohol using its volume and density. - Use the molecular weight of isopropyl alcohol to convert mass to moles.2. **Set up the ICE (Initial, Change, Equilibrium) table:** - Write initial concentrations. - Express changes in concentration in terms of a variable. - Write equilibrium concentrations in terms of the initial concentrations and the variable.3. **Apply the equilibrium constant expression:** - Substitute the equilibrium concentrations into the expression for the equilibrium constant and solve for the variable.4. **Calculate the percentage of isopropyl alcohol that remains undissociated:** - Use the obtained values to determine the undissociated part and convert it to a percentage.This detailed approach ensures that you correctly determine how much of the isopropyl alcohol remains undissociated at the given conditions.**Interactive Component**- **Submit Answer:** Click this button to submit your calculated answer.- **Try Another Version:** Click this button if you want to attempt another version of the problem.- **Attempts Remaining:** This count shows how many attempts you have left to answer the question.**Note:** This problem tests the understanding of chemical equilibrium concepts and the ability to apply them to a practical scenario.

In the given question we have to calculate the undissociated isopropyl alcohol at equilibrium. Given…

plus) [References] Isopropyl alcohol is the main ingredient in rubbing alcohol. It can decompose into acetone (the main ingredient in nail polish remover) and hydrogen gas according to the following reaction: C3H,OH(g) = C2H,CO(g)+ H2(g) At 180°C, the equilibrium constant for the decomposition is 0.45. If 43 mL (d = 0.785 g/mL) of isopropyl alcohol is placed in a 2.0 L vessel and heated to 180°C, what percentage remains undissociated at equilibrium?

plus) [References] Isopropyl alcohol is the main ingredient in rubbing alcohol. It can decompose into acetone (the main ingredient in nail polish remover) and hydrogen gas according to the following reaction: C3H,OH(g) = C2H,CO(g)+ H2(g) At 180°C, the equilibrium constant for the decomposition is 0.45. If 43 mL (d = 0.785 g/mL) of isopropyl alcohol is placed in a 2.0 L vessel and heated to 180°C, what percentage remains undissociated at equilibrium?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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