Please use the y from above (it is a constant number) What is your y from question 1? Provide the recurrence for the run-time of the code below. DO NOT solve for the closed form. foo(int A[]){ n=A.size; while (n> 1) { n = n-1; } count++; } n=A.size; mergeSort(A); foo(A[1..n/y]); foo(A[n/y+1...2n/y]);
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Please solve the following problem and show all work:
Given : y = 12
Step by step
Solved in 2 steps
- Implement the following Racket functions: You must use recursion, and not iteration. You may not use side-effects (e.g. set!). Transitive? Input: a list of pairs, L. Interpreting L as a binary relation, Transitive? returns #t if L is a transitive relation and #f otherwise. Examples: (display "Transitive? \n") (Transitive? '((a b) (b c) (a c))) ---> #t (Transitive? '((a a) (b b) (c c))) ---> #t (Transitive? '((a b) (b a))) ---> #f (Transitive? '((a b) (b a) (a a))) ---> #f (Transitive? '((a b) (b a) (a a) (b b))) ---> #t (Transitive? '())---> #tConsider the following code snippet. public int func2(int n) { if (n <= 5) return e; else if (n <= 100) return func2(n-1) return func2(n-1) + func2(n-2); } Please specify the recurrence relation modeling the runtime of this code fragment by filling in the blanks in following: A. if n _B. T(n) = _C_ otherwise Fill in part A: Enter your answer here Fill in part B: Enter your answer here Fill in part C: Enter your answer hereAnswer the given question with a proper explanation and step-by-step solution. Java N people are arranged in a circle.(Each assigned a number in sequence). Starting from the first, countdown , removing each k-th person from the list, while closing the circle. Determine the number of the last one remaining in the circle (k<=N) Hint: to solve this problem, use a list in which the reference field of the last element contains a link to the first element
- What is the value of the median-of-3 for the following list. [80, 47, 41, 21, 40, 68, 78, 18, 75, 46, 30] Notes: • Your answer should be a single valid, non-negative, literal Python int value. For example, 123 is a valid int literal. • This question is asking about before any partition operation is carried out. • This is not asking for the median-of-3 index. • You can pre-check your answer (to check it's a valid, non-negative, literal int).New JAVA code can only be added in between the grey lines of code (or lines 15 to 17, as shown in image).Question 7 Write a program, which returns the index of the minimum repeating element of the array in Jinear time and does just a single traversal of the array. You should use hash table functions like a hash set, hash map, etc. Ardil Subarray arrli+1...n-1] Return index ASAP duplicate is found The implementation can be seen here and requires Qn2) time, where n is the size of the input The idea is to traverse the array from right to left. If the element is seen for the first time insert it into the set; otherwise, update the minimum index to the element's index. Input: {5, 6, 3, 4, 3, 6, 4 } Output: The minimum index of the repeating element is 1 Input: {1 2, 3, 4, 5, 6 } Output: Invalid Input
- Find the recurrence relation of the code below and find the runtime analysis of it using any method. function mult(a, b) if b = 0: return 0 else if b is odd: return (mult(2a,[b/2 )+a) else: return (mult(2a, [b/2 ))Implement the following function. Hint: You should use a dictionary. def word_pattern (pattern: str, words: List [str]) -> bool: I ''Given a pattern and a word list, determine if the word list follows the same pattern. That is to say, ensure that pattern [j] pattern [k] only when words [j] == words [k] pattern [j] = pattern [k] means words [j] != words [k] Precondition: Assume pattern is all lowercase letters. >>> word_pattern ('aaaa', ['cat', 'cat', 'cat', 'cat']) True and == >>> word_pattern ('yoox', ['dog', 'cat', 'cat', 'fish']) True >>> word_pattern ('xy', ['cat', 'cat']) False >>> word_pattern('xoox', ['dog', 'cat', 'cat', 'fish']) FalseCan you give me example of quadratic probing in C++ ? The quadratic problem function has one input, call it m where m is a int. The return type is an int. For example, you have the serial number 2232012, quadProb(2232012) will return an int. Assume that the hash table size is 450. Assume that you are working with an uninitialized 2D array. Also write an insert() function to populate this 2D array.
- You are given an array-like data structure Listy which lacks a size method. It does, however, have an elementAt ( i) method that returns the element at index i in 0( 1) time. If i is beyond the bounds of the data structure, it returns -1. (For this reason, the data structure only supports positive integers.) Given a Listy which contains sorted, positive integers, find the index at which an element x occurs. If x occurs multiple times, you may return any index. Write code with explanationcan you please fix the AssertionError in this and also the code: (please don't use try and except or break/continue or recursion) def hike_unique(m: list[list[int]], start_point: tuple[int, int],end_point: tuple[int, int]) -> int: if start_point == end_point:return 0else:front_row = start_point[0]front_column = start_point[1]end_row = end_point[0]end_column = end_point[1]front_eva = m[front_row][front_column]end_eva = m[end_row][end_column]eva_diff = abs(front_eva - end_eva)if front_row == end_row:total_cost = eva_diff * (abs(front_column - end_column)) + 1elif front_column == end_column:total_cost = eva_diff * (abs(front_row - end_row)) + 1else:total_cost = eva_diff * (abs(front_row - end_row) + abs(front_column - end_column)) - 1return total_cost print(hike_unique(sample_map, (1, 1), (0, 0)) It should print 3 if the sample_map is >>> sample_map = [[1, 3], ... [0, 4]] if you do…develop a java program for :