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Please solve the 4th question only. Thanks!

Please solve the 4th question only. Thanks!

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please solve the 4th question only.
Thanks!

1. Simulate the following schematic in LTspice and demonstrate the output. vin K1 L1 L2 1 vout V1 L1. L2 25 1 SINE(0 170 60) Rser=0.1 .tran 100m 1) The inductor symbol with a dot is found by clicking on the "Sclect Component Symbol" button and selecting "ind2". 2) Press “.op" button and type in the spice code "K1 L1 L2 1", which tells LTspice that there is coupling between the inductors Ll and L2. The value can be between 0 and 1, with 1 indicating perfect coupling. 3) The values for the inductors are very high at 25H and 1H. These values are unrealistic but very high inductance ralues are needed to approximate an ideal transformer. The ratio of the inductance: here is 25. the sauare root of which is 5. i.e the voltage ratio of this transførmer. 4) The input peak voltage is 170 V to make 120 V RMS. You need to add a small series resistance (Rser = 0.10) to the input voltage source to avoid simulation error in LTspice. 5) Note that both sides of the transformer are grounded in schematic. This is done because circuits can't be left floating in LTspice simulations. In practice vou generally would not ground both sides of the transformer since this remo1es the isolation. 6) Run the simulation for 100ms. Obsere and compare the input and output wareforms. What do you see, and explain? 7) In practical, you can use smaller inductance (e.g. 25UH and luH), but add serial resistance (e.g. 10 N) to the inductors. Rerun simulations for 10 cycles, with frequencies of 60HZ, 10kHz, IMHZ, respectively. Compare the differences and why? S) Repeat 6) but change sine source into square wareform. Observe the waveforms.
Transcribed Image Text:1. Simulate the following schematic in LTspice and demonstrate the output. vin K1 L1 L2 1 vout V1 L1. L2 25 1 SINE(0 170 60) Rser=0.1 .tran 100m 1) The inductor symbol with a dot is found by clicking on the "Sclect Component Symbol" button and selecting "ind2". 2) Press “.op" button and type in the spice code "K1 L1 L2 1", which tells LTspice that there is coupling between the inductors Ll and L2. The value can be between 0 and 1, with 1 indicating perfect coupling. 3) The values for the inductors are very high at 25H and 1H. These values are unrealistic but very high inductance ralues are needed to approximate an ideal transformer. The ratio of the inductance: here is 25. the sauare root of which is 5. i.e the voltage ratio of this transførmer. 4) The input peak voltage is 170 V to make 120 V RMS. You need to add a small series resistance (Rser = 0.10) to the input voltage source to avoid simulation error in LTspice. 5) Note that both sides of the transformer are grounded in schematic. This is done because circuits can't be left floating in LTspice simulations. In practice vou generally would not ground both sides of the transformer since this remo1es the isolation. 6) Run the simulation for 100ms. Obsere and compare the input and output wareforms. What do you see, and explain? 7) In practical, you can use smaller inductance (e.g. 25UH and luH), but add serial resistance (e.g. 10 N) to the inductors. Rerun simulations for 10 cycles, with frequencies of 60HZ, 10kHz, IMHZ, respectively. Compare the differences and why? S) Repeat 6) but change sine source into square wareform. Observe the waveforms.
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