please label E/Z configuration and priority on products!! **Question 5:**For the following molecule, how many isomeric forms of alkenes could be made by reacting this with sodium isopropoxide (alkoxide of isopropyl alcohol) in isopropyl alcohol solution at 75°C?Show the process for the reaction and label and name all products expected to be made. Which one product is likely the major product? Remember E/Z as you name them.*Diagram Description:*The diagram shows a chlorinated organic molecule. The structure consists of a carbon chain with a chlorine (Cl) substituent. The details of the molecular structure are crucial for determining the possible alkenes formed in the reaction. The mechanism involves dehydrohalogenation, a base-induced elimination reaction (E2), to form alkenes from haloalkanes.---**Analysis & Explanation:**Reacting the given haloalkane with a strong base such as sodium isopropoxide results in the elimination of the halide ion (Cl⁻) and a hydrogen ion (H⁺) from adjacent carbon atoms, leading to the formation of an alkene. The reaction conditions at 75°C favor the formation of the most stable alkene, often leading to isomeric variations based on different possible positions for the double bond (E/Z isomerism).1. **Identify β-Hydrogens:** Recognize all hydrogen atoms adjacent to the carbon with the halide group.2. **Elimination Pathways:** - Draw possible alkene structures. - Consider the steric and electronic factors that stabilize each potential alkene. 3. **Naming E/Z Isomers:** Apply the Cahn-Ingold-Prelog (CIP) priority rules to name E (entgegen) and Z (zusammen) isomers.4. **Identify Major Product:** The most substituted (stable) alkene, following Zaitsev’s rule, is typically favored as the major product.This assessment helps predict the outcome of elimination reactions to synthesize desired alkenic products in organic chemistry.

An arrow always depicts from a region of high electron density to low electron density ; that is tail depicts region of high electron density and head depicts region of low electron density.Isopropoxide is strong base. so, E2 elimination takes place.Also, it is small base. so it abstracts proton to form more substituted alkene.In E2- elimination mechanism;There is simultaneous abstraction of proton as well as loss of halide leaving group to form alkene.It involves formation of transition state.major product is the alkene which is more substituted based on(zaitsev) saytzeff rule which is more thermodynamically stable.In this case also, trans alkene is the major product due to higher thermodynamic stability as two bulky groups are on opposite sides of double bond.we assign priorities to different substituents present across double bonds based on CIP rules.When two higher priority groups are on opposite sides of the double bond, it is trans,E-configuration.while, if substituents of higher priority are on same side of a double bond, it is called cis- configuration ,ZIn second structure, on one side of double bond two hydrogens are present, so E/Z configuration will not apply there.

Science

Chemistry

please show all steps involved with this question, thank you! 5. For the following molecule, how many isomeric forms of alkenes could be made by reacting this with sodium isopropoxidelalkoxide of isopropyl alcohol) in isopropyl alcohol solution at 75 Cº? Show the process for the reaction and label and name all products expected to be made. Which one product is likely the major product? Remember E/Z as you name them.

please show all steps involved with this question, thank you! 5. For the following molecule, how many isomeric forms of alkenes could be made by reacting this with sodium isopropoxidelalkoxide of isopropyl alcohol) in isopropyl alcohol solution at 75 Cº? Show the process for the reaction and label and name all products expected to be made. Which one product is likely the major product? Remember E/Z as you name them.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A ALEKS - Dona Luc - Lean H My Grades - 2021 Spring Term (2 X Tutor.com Learning Suite M Hey - lucdona7@gmail.com - Gm x www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-IBIZZhveDw7yX8A9043nt5P1XWJwAREDsbwIERg1UdvpRqH651Jk. O MATTER Solving applied density problems Mr. Auric Goldfinger, criminal mastermind, intends to smuggle several tons of gold across international borders by disguising it as lumps of iron ore. He commands his engineer minions to form the gold into little spheres with a diameter of exactly 6 cm and paint them black. However, his chief engineer points out that customs officials will surely notice the unusual weight of the "iron 3. ore" if the balls are made of solid gold (density 19.3 g/cm). He suggests forming the gold into hollow balls 3. instead (see sketch at right), so that the fake "iron ore" has the same density as real iron ore (5.15 g/cm). One of the balls of fake "iron ore," sliced in half. Calculate the required thickness of the walls of each hollow…
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Run 1 Run 2 Run 3 Run 4 Run# 1 2 3 4 Na₂S₂O3 0.005M 1 drop 1 drop 1 drop 1 drop Quantity. [Na2S2O3] stock [KI] stock [H202] stock k' KI 0.1M 2 drops KI 0.2M 2 drops 2 drops 2 drops Trial 1 (s) 0:34 0:07 1:11 0:12 Value 5.00 * 10^-3 2.00 * 10^-1 1.00 * 10^-3 0.0289 H₂O2 0.05M 1 drop H₂O2 0.1M 2 drops 2 drops 1 drop Trial 1 (s) 0:32 0:06 1:01 0:10 Trial 1 (s) 0:32 0:05 0:59 0:17 Trial 1 (s) 0:23 0:04 1:06 0:09 Trial 1 (s) 0:14 0:3 01:13 0:13 For the results you have shown in the Summary tables, provide the following sample calculations. Show your work in the space provided: Calculate the average reaction time for Run #1: For all Run #1 reaction times, use the Grubbs test to show whether you have an "outlier" in your data set.