please! in c++ General requirements: •No multiple return statements in a function. At most,1 return statementin a functionis allowed.No exit() function is allowed either. •No global variable is allowed. Constants are ok. •No reference to cin or cout in a function unless it isallowedexplicitly inthe question •Please include code that shows how you have tested these functions This is to practice the use of pointer. Write a function named “hasHelpOption”that accepts argc and argv (same data typesof command line arguments), it will return true if it has the argument of “/help”or “/?”or “—help”and false otherwise.Please show how this function is being used and tested.
please!
in c++
General requirements:
•No multiple return statements in a function. At most,1 return statementin a functionis allowed.No exit() function is allowed either.
•No global variable is allowed. Constants are ok.
•No reference to cin or cout in a function unless it isallowedexplicitly inthe question
•Please include code that shows how you have tested these functions
This is to practice the use of pointer.
Write a function named “hasHelpOption”that accepts argc and argv (same data typesof command line arguments), it will return true if it has the argument of “/help”or “/?”or “—help”and false otherwise.Please show how this function is being used and tested.
C++ Code for the given scenario is as follows:
#include <iostream>
#include <string.h>
using namespace std;
//hasHelpOption() definition
int hasHelpOption(int argc, char **argv)
{
for(int i=0;i<argc;++i)
if(((strcmp(argv[1],"--help"))==0) || ((strcmp(argv[1],"/help"))==0) || ((strcmp(argv[1],"/?"))==0))
return 1;
else
return 0;
}
//main function
int main(int argc, char** argv)
{
int x=0;
cout << "You have entered: "<<argv[1];
x=hasHelpOption(argc,argv);
if(x==1)
cout<<"\nTrue";
else
cout<<"\nFalse";
return 0;
}
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