Please help me with this how did they get that answer for T1. Im plugging in 8 x 9.8 / sin 40 + cos 40 + 50 = 50.39455. I don't get that part Image #1: My work Image #2: My ques
Please help me with this how did they get that answer for T1. Im plugging in 8 x 9.8 / sin 40 + cos 40 + 50 = 50.39455. I don't get that part Image #1: My work Image #2: My ques
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Please help me with this how did they get that answer for T1. Im plugging in 8 x 9.8 / sin 40 + cos 40 + 50 = 50.39455. I don't get that part
Image #1: My work
Image #2: My ques
Transcribed Image Text:Till this portion the sollution was correct. so I am
providing the siest correct solution.
Now putting the value of T₂ in 1972 we get,
Tising + Ticoso,
- sind ₂ = mg.
cos02
2
Ti{ sin81+0501
1 singz } = mg
T₁=
Hences
Hences
Now
Hences
mg
sind, +cos, tand ₂
given 0₁ = 40° and 2₂ = 50° and m= 8 kg.
T₁ =
=>
8x9-8
sin 40+ cos 40 tom 50°
T₁= 50-39455 Newton.
Transcribed Image Text:A 8 kg decoration hangs from the ceiling. It is
suspended by 2 wires. The first wire forms a
40° angle with the ceiling. The second wire forms a
50° angle with the ceiling.
a. Find the tension in the 2 wires (including
magnitude and direction)
b. Assuming the wire that forms the 40° angle with
the ceiling has a length of 0.3 metres, how far
below the ceiling is the decoration suspended?
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