Please help me answer how much volume of cell suspension needed (for 5*10^4 cells) in microliters. Pertinent Information shown in the image

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Please help me answer how much volume of cell suspension needed (for 5*10^4 cells) in microliters. Pertinent Information shown in the image. 

Determine the number of cells you have per ml of your cell suspension.
Number of cells counted in quadrant 1 =
46
Number of cells counted in quadrant 2 =
38
Number of cells counted in quadrant 3 =
56
Number of cells counted in quadrant 4 =
38
TOTAL number of cells for ALL 4 quadrants =
178
Number of cells per ml will equal:
[(total # of cells counted) divided by 4] X 104 =,
scientific notation)
_445,000_
cells/ml (use
B. Setting up a new culture of cells
1. You will need to determine the volume of your cell suspension needed to obtain 5 x 10^4 cells.
Use the value for cells per ml you determined above in Part A.
Example: If your cells per ml = 2 x 105
5 x 104 cells
= 0.25 ml, or 250 ul suspension
2 x 105 cells/ml
5 x 10^4 cells
0.12235955
= Volume of cell suspension needed:
mL
cells/mL
Volume of cell suspension needed (for 5 x 104 cells):
_microliters (uL)
These cells will be used to prepare "protein lysate" for western blot.
Transcribed Image Text:Determine the number of cells you have per ml of your cell suspension. Number of cells counted in quadrant 1 = 46 Number of cells counted in quadrant 2 = 38 Number of cells counted in quadrant 3 = 56 Number of cells counted in quadrant 4 = 38 TOTAL number of cells for ALL 4 quadrants = 178 Number of cells per ml will equal: [(total # of cells counted) divided by 4] X 104 =, scientific notation) _445,000_ cells/ml (use B. Setting up a new culture of cells 1. You will need to determine the volume of your cell suspension needed to obtain 5 x 10^4 cells. Use the value for cells per ml you determined above in Part A. Example: If your cells per ml = 2 x 105 5 x 104 cells = 0.25 ml, or 250 ul suspension 2 x 105 cells/ml 5 x 10^4 cells 0.12235955 = Volume of cell suspension needed: mL cells/mL Volume of cell suspension needed (for 5 x 104 cells): _microliters (uL) These cells will be used to prepare "protein lysate" for western blot.
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