please help find the Percent yeild and limiting regent given the collected dataVolume acetic acid: 20.0 mLVolume Isopentyl alcohol: 15.0 mLMass of Isopentyl Acetate collected: 9.775 gramsDensity of acetic acid: 1.049 g/mLDensity of Isopentyl alcohol: 0.813 g/mLi mostly need help with the yield Percent yield of isoamyl acetate based on the limiting reagent (showworking.include compound name or abbreviation)? Working need not be shown inconclusion.For reaction A ---> B5.00 g A x 1 mol Ax 1 mol B x 181 g B = 6.65 g B136 g A 1 mol A 1 mol Bmay be expressed as...5.00 g Ax (1mol A/136 g A) x (1 mol A/1 mol B) x (181 g B/1 mol B) = 6.65 g B Determine the limiting reagent. Sulfuric acid is a catalyst, and need not to beconsidered (show working).For example..For A + B ----> C20.00 g Ax 1mol Ax 1 = mole ratio AMW A 1 mol Acan be represented as.. 20.00 g Ax (1 mol A/MW A) x ( 1/1 mol A) = mol ratio A

Given: Volume acetic acid: 20.0 mL = 0.020 L Volume Isopentyl alcohol: 15.0 mL = 0.0150 L. Mass of…

Answered: please help find the Percent yeild and…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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please help find the Percent yeild and limiting regent given the collected data

Volume acetic acid: 20.0 mL
Volume Isopentyl alcohol: 15.0 mL
Mass of Isopentyl Acetate collected: 9.775 grams
Density of acetic acid: 1.049 g/mL
Density of Isopentyl alcohol: 0.813 g/mL

i mostly need help with the yield

Percent yield of isoamyl acetate based on the limiting reagent (show
working.include compound name or abbreviation)? Working need not be shown in
conclusion.
For reaction A ---> B
5.00 g A x 1 mol Ax 1 mol B x 181 g B = 6.65 g B
136 g A 1 mol A 1 mol B
may be expressed as...
5.00 g Ax (1mol A/136 g A) x (1 mol A/1 mol B) x (181 g B/1 mol B) = 6.65 g B

Determine the limiting reagent. Sulfuric acid is a catalyst, and need not to be
considered (show working).
For example..For A + B ----> C
20.00 g Ax 1mol Ax 1 = mole ratio A
MW A 1 mol A
can be represented as.. 20.00 g Ax (1 mol A/MW A) x ( 1/1 mol A) = mol ratio A

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