Please don't use the Chegg answer. We haven't discussed the phase difference equation 1. a. For the antireflective coating shown in the figure, how thick should the coating be to destructively interfere the incoming light and the reflected light (off the front of the glass) and why? Assume the light has a wavelength in air of 533 nm (green). b. What would the intensity be for 400 nm light and why? (Remember: intensity goes as the electric field squared!)

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Interference of Light

The word "constructive" signifies addition in interference. Constructive interference occurs when the path of the waves that start from the slit differs by 1 entire wavelength or in the intervals of the same. Hence, the waves that are presented on the screen are in phase (crest to crest/trough to trough). The waves interfering constructively forms bright fringes on the screen.