Please do this short answer question correctly We are going to roll 5 independent dice (like playing Yahtzee - but we will only roll once). The sum of the values of the dice can range anywhere from 5 (a roll of all 5 dice being a 1) to 30 (a roll of all 5 dice being a 6). I have determined that (to the 6th decimal) P(sum of values of the dice ≥ 8) = .997299. (i) Determine the P(sum of values of the dice ≤ 7) (to the 6th decimal). (ii) Provide a brief explanation as to the reason why your answer is correct.
Please do this short answer question correctly We are going to roll 5 independent dice (like playing Yahtzee - but we will only roll once). The sum of the values of the dice can range anywhere from 5 (a roll of all 5 dice being a 1) to 30 (a roll of all 5 dice being a 6). I have determined that (to the 6th decimal) P(sum of values of the dice ≥ 8) = .997299. (i) Determine the P(sum of values of the dice ≤ 7) (to the 6th decimal). (ii) Provide a brief explanation as to the reason why your answer is correct.
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 33E: Find the probability of each event. Drawing 5 orange cubes from a bowl containing 5 orange cubes and...
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Please do this short answer question correctly
We are going to roll 5 independent dice (like playing Yahtzee - but we
will only roll once). The sum of the values of the dice can range anywhere from 5 (a roll of
all 5 dice being a 1) to 30 (a roll of all 5 dice being a 6). I have determined that (to the 6th
decimal) P(sum of values of the dice ≥ 8) = .997299. (i) Determine the P(sum of values
of the dice ≤ 7) (to the 6th decimal). (ii) Provide a brief explanation as to the reason why
your answer is correct.
Expert Solution
Step 1: Probability calculated.
There arte 5 dice.Each dice has 6 faces.Therfore the number of sample points is =7776
Let X be the sum of faces of dice,then
Let A be the event {X: } then A will contain (1,1,1,1,1) : 1 time giving X=5
(1,1,1,1,2) : times giving X=6
and (1,1,1,2,2) : =10 times giving X=7
Therefore
P()=P(X=5)+P(X=6)+P(X=7) = (1+5+10)/7776 == 0.002058
Moreover P(X8) = 1-P(X<8)= 1-P(X7)= 1- 0.002058 =0.997942, which does not match to your calculation.
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