Please answer P(Z> -0.34), P(0.15

Q: n=9,p=0.3x<3

A: Given: A binomial trial with n=9, p=0.3. The probability of binomial experiment is given as…

Q: Where do you get 0.9049 or it should be 0.4049 according to z table?

A: Given that, μ=43 yearsσ=5yearsn=30 The probability that the average age of the group is greater than…

Q: 5.75(+/- 0.03) + 0.833 (+/- 0.002) - 8.021 (+/- 0.001) = ? Select one: a. -1.438 (+/- 0.027) b.…

A:

Q: P=( 14,000 x 0.014+1/2 x 0.00238 x 51.332 x 0.412 x 34.3) x 51.33

A: we have given that  some operation + ,× , /

Q: Suppose P(A) = 0.48 and P(B) = 0.62. Can A and B be mutually exclusive? Why or why not.

A: We know that, mutually exclusive events are  events which can not happen at the same time.

Q: Find P(1.73< Z < 2.16)     a. 0.4334 b. 0.0263 c. 0.02641 d. 0.9428

A:

Q: Find P(Z < 2.84)     .5375     .9575     .8098     .9977

A:

Q: yhat=4.302x-3.293 where x is 20

A: Note: Hey there, Thank you for the question. Since the question is not clear to us, we have obtained…

Q: What is P( -1.03 < Z < 0.57 )?

A: The question is about standard normal distribution Introduction : Standard normal distribution. Z is…

Q: If P(A) = 0.7, P(B) =0.2, and A and B are mutually exclusive, find P (A or B). P(4 or B) = D

A:

Q: What is the opposite and absolute value of negative 4.06

A:

Q: A population of values has a normal distribution with u = 129.5 and o = 69.1. You intend to draw a…

A: Let, X=The population of values Given that X follows a normal distribution with mean= 129.5 and…

Q: Elimination Tournaments In an elimination tournament the teams are arranged in opponent pairs for…

A: The total number of teams in the elimination tournament =4 The total number of rounds to be played…

Q: Given x - (32,225). Find P(x < 22).

A: Given that X follows normal distribution with mean 32 and variance 225. That is, mu=32 and…

Q: 0.13+15.04(x+3)=0.14+15.54

A: x=-1.96 Explanation is given below

Q: find P (Z > 1.21) = find P (Z < 1.60) = find P (0.59 < Z < 1.78) =

A: 1) P (Z &gt; 1.21) =?

Q: If P(A) = 0.5 and P(B) = 0.80, then P(A or B) must be 0.95.   TRUE or FALSE

A: From the provided information, P (A) = 0.5 and P (B) = 0.80

Q: find p (z<0.92) refer to the table of x-scores

A: p (z&lt;0.92) =?

Q: Find P (z > 2.59)

A: We have to find  P (z &gt; 2.59) = ?

Q: What is P(X>6)?

A:

Q: P(0.68<:<2.18):

A: Z~N(0,1) To find:

Q: why did you add .032 when you did not list it p(x=6)?

A: The probability distribution table of X provided in the question is as follows…

Q: p(-2.75<z<-0.49)

A: Given that z is standard normal random variable:

Q: P(−1.14 ≤ z ≤ 2.63)

A: Let Z be the random variable from normal distribution then we will find the probability P(−1.14 ≤ z…

Q: P(Z 2 0.75) (Round to the hundredths)

A: We have to find probability of z greater than or equal to 0.75

Q: In Major League Baseball, the coefficient of determination(r2) of a player salary and total number…

A: Given: . Coeffient of determination,r2=0.28

Q: where did  you get 0.5 from

A: The mean of the distribution, The standard deviation of the distribution,

Q: n=10,p=0.3,x<4

A: The formula for binomial probability is represented as :   Given: n=10 p=0.3 x&lt; 4

Q: P(-1.15 < Z < 1.56) (Round to the hundredths)

A: Using Excel formula, "=NORM.S.DIST(1.56,TRUE)", the value of PZ≤1.56 is obtained as 0.94. Using…

Q: P(-3 < Z < 3) (Round to the thousandths)

A: According to the given information, we have P(-3≤Z≤3)

Q: y=3.0161x-5819.5

A: Topic:- geometry

Q: Find the value of x: 1.

A:

Q: The p-value is not 0.0149.

A: Solution-: We want to find p-value for the given RBD design

Q: Find P(1.73< Z < 2.16)

A:

Q: Find P (-0. 55 < z < 2.51)

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Q: P(Z = 0.76) %3D O 0.71 0.22 J0.29 O 0.78

A: Note that Z (standard Normal) is  a continuous random variable.

Q: Find P( -2.56 < z < <z<1.92)   a. 0.967   b. 0.241   c. -0.241   d. 0.032

A: Followings are the explanation of the question   Let z be the standard normal variables follows the…

Q: P(Z < 0.58) = %3D 0. J0.2 J0.8 0.28 0.72

A: Given that, P(Z&lt;0.58)

Q: n=9, p=0.2x<3

A: Here we need to find P(X&lt;3).

Q: Find z1: 1. P(z1<z<2.98)=.1117

A:

Q: P(Z > -0.05) (Round to the hundredths)

A: Use the standard normal table, to find the required probability.

Q: Find P (1.23 <z <2.35)

A:

Q: P ( -2.53 &lt; z &lt; 0.65)

A: The probability is,

Q: 38.122+y (180.158

A:

Q: x=-.8+0/(1+.05)+(120/(1+.05)2

A:

Q: P= 2,754 0.55D, 2.52C; +252G; +576PE; + 1,750Fi (0.12) (1.1) (135) (200) (450) P₁ = Annual employee…

A: The provided information is as follows:The regression equation is given as .

Q: Let P(A) = 0.2 and P(B) = 0.5. If P(A|B) = 0.3, calculate P(A and B

A: Given data, P(A) = 0.2   P(B) = 0.5 P(A|B) = 0.3 P(A and B)=?