0 1.73 2.16

Q: Step 1: Enter the number of degrees of freedom. Step 2: Select one-tailed or two-tailed. O…

A: The mean amount of gamma radiation needed to sterilize a colony of tardigrades is not equal to 1150…

Q: Find z given that P(.24 <Z <z) = .12

A:

Q: p(z < 1.29)

A: standard normal distribution Z~N(0,1) P(z&lt;1.29) = ?

Q: Find P(-1.40 < Z < 0)     .4192     .1259     .4357     .8907

A: Solution: Let Z be the standard normal random variable with mean μ=0 and standard deviation σ=1…

Q: To find P(x<2.35) where do you shade?

A: Left side

Q: Find the interval values for Z such that P(-z<Z<z)= 0.9886.

A: P(-z&lt;Z&lt;z) =0.9886.·.  x=1-0.9886         =0.0114

Q: P(z>1.2)

A: Given problem Given that   P(z&gt;1.2)   Ans) P( z&gt;1.2 ) is, = 1 - P( z ≤ 1.2 )

Q: P(Z<1.89) (less than or equal to)

A: Given that.   X~N( 0 , 1 )   μ=0  , ?=1 (for standard normal distribution)    Z-score =( x - μ )/?

Q: Calculate P(Z < 1.5)

A:

Q: If m rst = 164, what is m<RVT?

A:

Q: P(x < 17.872)

A: Let's take the given  Sample size n=33 from a population, with mean=16 and standard deviation=8.4…

Q: P(1.15 < Z < 2.77) =

A: X~N( 0 , 1 )   μ=0 , ?=1 (for standard normal distribution)   Z-score =( x - μ )/?

Q: P (Z<1.8572)

A: Answer - Find   P (Z&lt;1.8572)

Q: P(x) = . Let and let = 10. Find P(9) x!

A: We have to find p(9)

Q: P(0.51 ≤ Z ≤ 1.4) =

A: Draw the normal curve and shade the area between z=0.51 and z=1.4.

Q: (h) P(1.26 ≤ Z ≤ 2.50) (1) P(1.90 ≤ Z) (1) P(|Z| ≤ 2.50)

A: It is given that the standard normal random variable Z with mean 0 and variance 1.   Note: The…

Q: p(0 < z < 1.30)= p(0 < z < 1.83)= p(1.30 < z < 1.83)=

A: Given that:Z is standard normal Distributed with i.e. mean µ =0 and standard deviation σ =1 By…

Q: P(X ≤ 1). n = 5, p = 0.6

A: