Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. Block B starts from rest and then moves to the right with a variable acceleration given by the acceleration-
Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE.
Block B starts from rest and then moves to the right with a variable acceleration given by the acceleration-time curve.
Determine:
(a) the acceleration
(b) the velocity of block A at t = 3.71 s.
*dont copy other experts' answer, i'm looking for a different approach in solution
can you please verify which among these two solutions is coreect?
Solution 1:
Let T is the tension in each rope so 3T is acting on block B and 2T is acting on block A.
So , 3T×aB=2T×aA×aB=2T×aA
Hence,aA =32aBHence,aA =32aB
acceleration of block B = 0.29 ft/s2 (from graph)
a)acceleration of block A (t=3.71s)= 32×0.29 ft/s2 =0.435 ft/s232×0.29 ft/s2 =0.435 ft/s2
b) Velocity of block B at (t = 3.71 s) = Area under the graph = 2ft/s2×1s−1ft/s2×1s+12×(2ft/s2+0.29ft/s2)×1.71s =2.96ft2ft/s2×1s-1ft/s2×1s+12×(2ft/s2+0.29ft/s2)×1.71s =2.96ft/s
Velocity of block A at (t=3.71s) = 32×vB=32×2.96ft/s=4.44 ft/s
Solution 2: *check the last attached image
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