13. A 5.200-kilogram steel block is launched across a frictionless surface at 2.755 m/s, towards a 0.416-kilogram steel block initially at rest. After impact, the smaller block is directed up a rough ramp inclined at an angle of 15.0° above the horizontal. The coefficient of static friction between the ramp and the block is Us = 0.308, but the kinetic friction coefficient is to be determined. (i) What are the velocities of each block after the collision? (ii) If there was no friction on the ramp, to what height (vertically) would the smaller block rise along the ramp? (If you do not trust your answer to (i), you may use assumed values of v, = 2.347 m/s and v, = 5.102 m/s.) (iii) As it is, however, the ramp is "rough" so the block only rises to a height of 0.654 m above its starting position. How much work did kinetic friction do on the block? (iv) Calculate the coefficient of kinetic friction, µk, between the block and the ramp. (v) Once the block comes to rest, will static friction cause it to remain at rest, or will it slide back down? Justify your answer.

Elements Of Electromagnetics
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Hello I need help finding the solutions for part 4 and 5 (iv & v ) The solutions found for the first three parts are in the separate image. 

13. A 5.200-kilogram steel block is launched across a frictionless surface at 2.755 m/s,
towards a 0.416-kilogram steel block initially at rest. After impact, the smaller block
is directed up a rough ramp inclined at an angle of 15.0° above the horizontal. The
coefficient of static friction between the ramp and the block is µs = 0.308, but
the kinetic friction coefficient is to be determined.
(i) What are the velocities of each block after the collision?
(ii) If there was no friction on the ramp, to what height (vertically) would the smaller block rise along the ramp?
(If you do not trust your answer to (i), you may use assumed values of v, = 2.347 m/s and v, = 5.102 m/s.)
(iii) As it is, however, the ramp is “rough" so the block only rises to a height of 0.654 m above its starting position.
How much work did kinetic friction do on the block?
(iv) Calculate the coefficient of kinetic friction, µk, between the block and the ramp.
(v) Once the block comes to rest, will static friction cause it to remain at rest, or will it slide back down? Justify
your answer.
Transcribed Image Text:13. A 5.200-kilogram steel block is launched across a frictionless surface at 2.755 m/s, towards a 0.416-kilogram steel block initially at rest. After impact, the smaller block is directed up a rough ramp inclined at an angle of 15.0° above the horizontal. The coefficient of static friction between the ramp and the block is µs = 0.308, but the kinetic friction coefficient is to be determined. (i) What are the velocities of each block after the collision? (ii) If there was no friction on the ramp, to what height (vertically) would the smaller block rise along the ramp? (If you do not trust your answer to (i), you may use assumed values of v, = 2.347 m/s and v, = 5.102 m/s.) (iii) As it is, however, the ramp is “rough" so the block only rises to a height of 0.654 m above its starting position. How much work did kinetic friction do on the block? (iv) Calculate the coefficient of kinetic friction, µk, between the block and the ramp. (v) Once the block comes to rest, will static friction cause it to remain at rest, or will it slide back down? Justify your answer.
Velocity of larger block is 2.347 m/s after
collision
Velocity of smaller block is 5.019 m/s after
collision
In absence of friction, the block moves up
to a height of 1.328 m on the ramp
Work done by kinetic friction is 2.7479 J
Transcribed Image Text:Velocity of larger block is 2.347 m/s after collision Velocity of smaller block is 5.019 m/s after collision In absence of friction, the block moves up to a height of 1.328 m on the ramp Work done by kinetic friction is 2.7479 J
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