Please answer question 11 part A and B **Part B: Calculating Enthalpy of Reaction***Objective:*Calculate the enthalpy of the reaction:\[ 4\text{B(s)} + 3\text{O}_2\text{(g)} \rightarrow 2\text{B}_2\text{O}_3\text{(s)} \]*Given Information:*1. \(\text{B}_2\text{O}_3\text{(s)} + 3\text{H}_2\text{O(g)} \rightarrow 3\text{O}_2\text{(g)} + \text{B}_2\text{H}_6\text{(g)}, \quad \Delta H^{\circ}_A = +2035 \text{ kJ}\)2. \(2\text{B(s)} + 3\text{H}_2\text{(g)} \rightarrow \text{B}_2\text{H}_6\text{(g)}, \quad \Delta H^{\circ}_B = +36 \text{ kJ}\)3. \(\text{H}_2\text{(g)} + \frac{1}{2}\text{O}_2\text{(g)} \rightarrow \text{H}_2\text{O(l)}, \quad \Delta H^{\circ}_C = -285 \text{ kJ}\)4. \(\text{H}_2\text{O(l)} \rightarrow \text{H}_2\text{O(g)}, \quad \Delta H^{\circ}_D = +44 \text{ kJ}\)*Instruction:*Express your answer with the appropriate units.[**ΔH° =** **Value** **Units**]**Note:** Click "View Available Hint(s)" for assistance with the calculation steps. ### Understanding Hess's LawHess's law states that "the heat released or absorbed in a chemical process is the same whether the process takes place in one or in several steps." Here are important rules to remember:1. **Addition of Reactions:** When two reactions are added, their enthalpy values are also added.2. **Reversing a Reaction:** If a reaction is reversed, the sign of its enthalpy value is changed.3. **Multiplying Reaction Coefficients:** If the coefficients of a reaction are multiplied by a factor, the enthalpy value is multiplied by the same factor.### Problem Statement**Part A:** Calculate the enthalpy of the reaction:\[ 2\text{NO}(g) + \text{O}_2(g) \rightarrow 2\text{NO}_2(g) \]Using the following reactions and enthalpies of formation:1. \(\frac{1}{2}\text{N}_2(g) + \text{O}_2(g) \rightarrow \text{NO}_2(g)\), \(\Delta H_A^\circ = 33.2 \text{ kJ}\)2. \(\frac{1}{2}\text{N}_2(g) + \frac{1}{2}\text{O}_2(g) \rightarrow \text{NO}(g)\), \(\Delta H_B^\circ = 90.2 \text{ kJ}\)**Task:** Express your answer with the appropriate units.**Input Box:** Calculate and enter the value for \(\Delta H^\circ\).```plaintext\(\Delta H^\circ = \text{Value} \quad \text{Units}\)```Click to view available hints if needed.

Answered: Image /qna-images/answer/5a5d7fbb-5bbe-4c58-b564-ea8ba56b3a90.jpg

Answered: Please answer question 11 part A and B

Please answer question 11 part A and B

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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