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Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Formation and Isoelectric Point (pI) of the Di-peptide Glu-Lys**

**1. Introduction:**
This exercise involves drawing the di-peptide formed from glutamic acid (Glu) and lysine (Lys) at neutral pH, and determining whether its isoelectric point (pI) is acidic, neutral, or basic.

**2. Description of Amino Acids:**

(a) **Lysine (Lys):**
```
  H2N    O
   |      ||
H2N-CH- C - OH 
   |
   CH2
   |
   CH2
   |
   CH2
   |
   CH2
   |
   NH2
```

**Structure:**
- The structure of lysine includes an amino group (H2N) and a carboxyl group (COOH). 
- The side chain (R group) is four CH2 groups ending in an amino group (NH2).

(b) **Glutamic Acid (Glu):**
```
  H2N    O
   |      ||
H2N-CH- C - OH 
   |
   CH2
   |
   CH2
   |
   CH2
   |
   |C
   O |
  OH
```

**Structure:**
- The structure of glutamic acid consists of an amino group (H2N) and a carboxyl group (COOH). 
- The side chain is two CH2 groups followed by a carboxyl group (COOH).

**3. Formation of Glu-Lys Di-peptide:**
To form the di-peptide Glu-Lys, the carboxyl group of Glu reacts with the amino group of Lys, releasing a molecule of water in a condensation reaction:
```
  H2N    O                 H2N    O
   |      ||                    |      ||
H2N-CH- C - OH + H2N-CH- C - OH --
   |                            + H2O
   CH2                                |   |
   |                                 CH2  CH2
   CH2                                | |
   |                                CH2  CH2
   CH2                                | |
   |                                C - NH
   COO                                NH2 -Oh

```

**4. Isoelectric Point (pI) Consideration:**
- The isoelectric
Transcribed Image Text:**Formation and Isoelectric Point (pI) of the Di-peptide Glu-Lys** **1. Introduction:** This exercise involves drawing the di-peptide formed from glutamic acid (Glu) and lysine (Lys) at neutral pH, and determining whether its isoelectric point (pI) is acidic, neutral, or basic. **2. Description of Amino Acids:** (a) **Lysine (Lys):** ``` H2N O | || H2N-CH- C - OH | CH2 | CH2 | CH2 | CH2 | NH2 ``` **Structure:** - The structure of lysine includes an amino group (H2N) and a carboxyl group (COOH). - The side chain (R group) is four CH2 groups ending in an amino group (NH2). (b) **Glutamic Acid (Glu):** ``` H2N O | || H2N-CH- C - OH | CH2 | CH2 | CH2 | |C O | OH ``` **Structure:** - The structure of glutamic acid consists of an amino group (H2N) and a carboxyl group (COOH). - The side chain is two CH2 groups followed by a carboxyl group (COOH). **3. Formation of Glu-Lys Di-peptide:** To form the di-peptide Glu-Lys, the carboxyl group of Glu reacts with the amino group of Lys, releasing a molecule of water in a condensation reaction: ``` H2N O H2N O | || | || H2N-CH- C - OH + H2N-CH- C - OH -- | + H2O CH2 | | | CH2 CH2 CH2 | | | CH2 CH2 CH2 | | | C - NH COO NH2 -Oh ``` **4. Isoelectric Point (pI) Consideration:** - The isoelectric
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