Please, Add a display function that prints the stack using FIFO(first in first out) {printed in the sequence they were entered} Do not use for loop. this is stack implementation. not your normal for loop. I can do it using for loop. so if you don't know, don't try. I will downvote for sure!!
Please, Add a display function that prints the stack using FIFO(first in first out) {printed in the sequence they were entered}
Do not use for loop. this is stack implementation. not your normal for loop. I can do it using for loop. so if you don't know, don't try. I will downvote for sure!!
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define max 5
int push(char stack[max][80], int *top, char data[80])
{
if(*top == max -1)
return(-1);
else
{
*top = *top + 1;
strcpy(stack[*top], data);
return(1);
}
}
int pop(char stack[max][80], int *top, char data[80])
{
if(*top == -1)
return(-1);
else
{
strcpy(data, stack[*top]);
*top = *top - 1;
return(1);
}
}
int main()
{
char stack[max][80], nm[80];
int top,ch,reply;
top = -1; // Initialize Stack
printf("\tMENU");
printf("\n----------------------------\n");
printf(" 1. PUSH\n");
printf(" 2. POP\n");
printf(" 3. EXIT\n");
printf("----------------------------\n");
while(1)
{
printf("Choose operation : ");
scanf("%d", &ch);
switch (ch)
{
case 1 : // push
printf("\nEnter string : ");
scanf("%s",nm);
reply = push(stack,&top,nm);
if(reply == -1)
printf("\n Stack is Full.\n");
else
printf("'%s' is Pushed in Stack.\n\n",nm);
break;
case 2 : // pop
reply = pop(stack, &top,nm);
if(reply == -1)
printf("\n Stack is Empty \n");
else
printf("Popped string is : %s\n",nm);
printf("\n");
break;
case 3 :
exit(0);
default:
printf("Invalid operation \n");
}
}
return 0;
}
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